Quark confinement and meson confinement

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SUMMARY

The discussion centers on the concepts of quark confinement and meson confinement, particularly how color confinement prevents color-charged particles from existing in isolation. It is established that mesons, formed from a colored quark and its corresponding anticolor, are color-neutral and can exist outside of protons due to the phenomenon of asymptotic freedom, where the strong force weakens at high energies. Participants clarify that confinement requires infinite energy to separate color charges, while asymptotic freedom is a high-energy phenomenon that does not directly imply confinement. The relationship between these concepts is debated, emphasizing that asymptotic freedom is neither a necessary nor sufficient condition for confinement.

PREREQUISITES
  • Understanding of quantum chromodynamics (QCD)
  • Familiarity with the concepts of color charge and color neutrality
  • Knowledge of asymptotic freedom in particle physics
  • Basic principles of particle interactions and scattering processes
NEXT STEPS
  • Explore the implications of asymptotic freedom in quantum chromodynamics
  • Research lattice QCD calculations related to confinement potentials
  • Investigate the role of color charge in particle interactions
  • Examine theoretical frameworks for confinement beyond lattice QCD, such as superconductor-inspired ideas
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Physicists, particularly those specializing in particle physics and quantum field theory, as well as students and researchers interested in the fundamental interactions of quarks and gluons.

  • #31
tom.stoer said:
So we agree. The argument is fine for compact spaces but there's a loophole for non-compact spaces - unfortunately I don't know how to save the idea - but I think I do not have to be more clever than Witten and Jaffe :-)

Yes, but since the argument fully breaks down for QED, I wouldn't call it a loophole but complete lack of argument.

I believe that a single quark in a sea of gluons is a valid sector of QCD, though not one realized in Nature, because the real universe contains many quarks and is colorless.
 
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  • #32
A. Neumaier said:
Yes, but since the argument fully breaks down for QED, I wouldn't call it a loophole but complete lack of argument.
Certainly not. It is used in all canonical, non-perturbative approaches to QCD! There are numerous groups doing exactly that.

The appraoch is always identical:
- solve Gauss law = eliminate unphysical degrees of freedom
- solve QCD in the color-neutral sector
 
  • #33
tom.stoer said:
Certainly not. It is used in all canonical, non-perturbative approaches to QCD! There are numerous groups doing exactly that.

The appraoch is always identical:
- solve Gauss law = eliminate unphysical degrees of freedom
- solve QCD in the color-neutral sector

But the second step involves an additional assumption. One could instead solve QCD in a colored sector, and would get meaningful mathematical results at the same level of approximation as for the color-neutral case. But since this is not useful for phenomenology, it is not being done.
 
  • #34
That's not true. As I said G(x) ~ 0 which is (in the Dirac-formalism) translated into G(x)|phys> = 0 requires Q|phys> = 0. So if we restrict to localized states there should be no difference between the spectrum in R³ and T³ and therefore color-neutrality is not assumptions but strictly proven.

The only assumption I can see is that T³ and R³ have (approximately) the same physical content (for localized states / hadron spectroscopy, form factors, ...).

[But afaik there is not one single mathematically exact result b/c already at the classical level one cannot get rid of all gauge = Gribov ambiguities which is required for solving the Gauss law constraint. So there are always artefacts like isolated Gribov copies or ghosts or ... The only way out is lattice QCD where gauge fixing is not required b/c the path integral over the gauge group is finite and gauge fixing can safely be replaced by gauge averaging (it may slow down computations; I don't know]
 
  • #35
tom.stoer said:
That's not true. As I said G(x) ~ 0 which is (in the Dirac-formalism) translated into G(x)|phys> = 0 requires Q|phys> = 0. So if we restrict to localized states there should be no difference between the spectrum in R³ and T³ and therefore color-neutrality is not assumptions but strictly proven.

The unproved assumption used in your argument is that the states are localized.
But precisely this assumption is violated in charged stated, because of infrared issues, which are closely related to the infinite volume limit, i.e., noncompactness.
This can already be seen in QED, where the IR problem is tractable, and the physical charged states (involving a coherent admixture of photons) are associated to superselection rules coming from asymptotic conditions at infinity. There is no reason to believe that in QCD the situation should be much simpler than in QED.
 
  • #36
So you say one should throw away all QCD results based on T³
 
  • #37
tom.stoer said:
So you say one should throw away all QCD results based on T³

I never said that. One should view the QCD results based on the torus as results that may need modification in the infinite-volume limit, at least those modifications that are already needed in case of QED.
 
  • #38
There are of course known differences regarding topology, large gauge transformations / winding number, gauge field zero modes etc. It would not be a disaster to add some more topics to that list.

But: as long as we do not know how the topology of the universe looks like, this is academic; I can't believe (and I hope that I am not completely wrong) that the cosmological constant doe not affect the QCD spectrum :-)
 
  • #39
tom.stoer said:
There are of course known differences regarding topology, large gauge transformations / winding number, gauge field zero modes etc. It would not be a disaster to add some more topics to that list.

But: as long as we do not know how the topology of the universe looks like, this is academic; I can't believe (and I hope that I am not completely wrong) that the cosmological constant doe not affect the QCD spectrum :-)

You have here a double negation. Did you intend that not not x = x? I'd be surprised...

For the purposes here on earth, the universe can be regarded as being topologically
flat, and gravitation can be treated as an external field. Under these conditions, I believe that both QED and the standard model or its variants are consistent.
 
  • #40
Thanks for correcting me: As long as we do not know how the topology of the universe looks like, this is academic; I can't believe that the cosmological constant does affect the QCD spectrum.
 

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