Question about a bunsen burner lab?

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Discussion Overview

The discussion revolves around a lab write-up concerning the temperature of a bunsen burner flame, specifically focusing on how to account for the mass of water that evaporates into steam during the experiment. The participants explore methods to incorporate this factor into the energy calculation used in the lab.

Discussion Character

  • Homework-related, Technical explanation

Main Points Raised

  • One participant describes the lab setup involving heating copper and measuring temperature changes in water, highlighting the need to consider evaporated water in calculations.
  • Another participant suggests weighing the copper strip and water before the experiment as a starting point for including evaporated water in the calculations.
  • A subsequent reply confirms that the initial weights were recorded but does not clarify if post-experiment weights were taken.

Areas of Agreement / Disagreement

Participants have not reached a consensus on how to incorporate the evaporated water into the calculations, and the discussion remains unresolved regarding the best approach.

Contextual Notes

There is a lack of detail on how the mass of the evaporated water can be quantitatively included in the energy equation, and the implications of neglecting this factor are not fully explored.

chemishard93
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Okay, I have a lab write-up due tomorrow and I am completely stumped on one of my conclusion questions.

The lab was an attempt to figure out the temperature of a bunsen burner flame. We did this by using a bunsen burner to heat copper and then immersing the copper into a cup of water and recording the temperature change. The question is asking us to take into account the small mass of water neglected in the equation that was evaporated into hot steam when the copper was immersed.

The equation was: -(mass copper)(Cp copper)(T3-T1)=(mass water)(Cp water)(T3-T2)

T1=burner temperature
T2=intial water temperature
T3=final water temperature

Okay...THE QUESTION I CAN'T FIGURE OUT IS: It takes about 2.26 kilojoules of energy to evaporate each gram of water. Suggest a way to include the evaporated water in your calculation.

I have tried to come up with solutions. However, none of them seem to make much sense...

PLEASE HELP! NEED HELP WITHOUT 3-4 HOURS!
 
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Well... if you were to weigh the copper strip and the water in the calorimeter before heating and immersing the heated strip, you might have a good start on it.
 
We did that, actually. Haha - sorry! Forgot to mention that.
 
And, did you weigh it afterwards?
 

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