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Question about a bunsen burner lab?

  1. Feb 26, 2009 #1
    Okay, I have a lab write-up due tomorrow and I am completely stumped on one of my conclusion questions.

    The lab was an attempt to figure out the temperature of a bunsen burner flame. We did this by using a bunsen burner to heat copper and then immersing the copper into a cup of water and recording the temperature change. The question is asking us to take into account the small mass of water neglected in the equation that was evaporated into hot steam when the copper was immersed.

    The equation was: -(mass copper)(Cp copper)(T3-T1)=(mass water)(Cp water)(T3-T2)

    T1=burner temperature
    T2=intial water temperature
    T3=final water temperature

    Okay...THE QUESTION I CAN'T FIGURE OUT IS: It takes about 2.26 kilojoules of energy to evaporate each gram of water. Suggest a way to include the evaporated water in your calculation.

    I have tried to come up with solutions. However, none of them seem to make much sense...

    PLEASE HELP!!!! NEED HELP WITHOUT 3-4 HOURS!!!!
     
  2. jcsd
  3. Feb 26, 2009 #2

    chemisttree

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    Well... if you were to weigh the copper strip and the water in the calorimeter before heating and immersing the heated strip, you might have a good start on it.
     
  4. Feb 26, 2009 #3
    We did that, actually. Haha - sorry! Forgot to mention that.
     
  5. Feb 26, 2009 #4

    chemisttree

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    And, did you weigh it afterwards?
     
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