Question about a solid cylinder

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The discussion centers on calculating the angular acceleration of a solid cylinder pivoted about a frictionless axle, with a moment of inertia of 8 kg m². A downward force of 3 N is applied at an outer radius of 2 m, while an 8 N force is applied to the right at an inner radius of 0.7 m. The user expresses uncertainty in approaching the problem, seeking guidance on the relevant physics concepts, particularly torque and angular motion equations.

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Homework Statement



A solid cylinder is pivoted about a frictionless axle as shown. A rope wrapped around the outer radius of 2 m exerts a downward force of 3N. A rope wrapped around the inner radius of 0.7 m exerts a force of 8 N to the right. The moment of inertia of the cylinder is 8 kg m^2. Find the angular acceleration.

Homework Equations



Don't even know whre to start of since i never had a problem like this in mastering physics hm. (this is from a review sheet of my physics test on Tuesday)

The Attempt at a Solution


No idea, I'm in hopes you can orientate me in this one.
 

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ScienceGeek24 said:

Homework Statement



A solid cylinder is pivoted about a frictionless axle as shown. A rope wrapped around the outer radius of 2 m exerts a downward force of 3N. A rope wrapped around the inner radius of 0.7 m exerts a force of 8 N to the right. The moment of inertia of the cylinder is 8 kg m^2. Find the angular acceleration.

Homework Equations



Don't even know whre to start of since i never had a problem like this in mastering physics hm. (this is from a review sheet of my physics test on Tuesday)

The Attempt at a Solution


No idea, I'm in hopes you can orientate me in this one.

You want to review the concepts of angular motion including torque, moment of inertia, angular momentum, angular velocity, angular acceleration. All of these things have their counterparts in linear motion, and the forms of the equations that relate the quantities is the same, too (which makes things easier to remember!).
 
I think i should. But i'll get back to you if i haven't been able to solve it.
 

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