Question about a Windmill / Turbine

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SUMMARY

The discussion centers on a physics problem involving turbines and windmills, specifically comparing the moving speed of air molecules in two scenarios: one with reversed steady windmills between movable windmills and another with movable reversed windmills among movable windmills actuated by wind power. Key equations mentioned include kinetic energy (K = 0.5mv²) and work-energy principles (Wtot = K2 - K1 = ΔK). Participants express confusion over the terminology used, particularly "reverse windmills," indicating a need for clarification from a professor or more knowledgeable source.

PREREQUISITES
  • Understanding of basic physics concepts such as kinetic energy and work-energy principles.
  • Familiarity with motion equations, including E = ½mv² and F = ma.
  • Knowledge of wind turbine mechanics and aerodynamics.
  • Ability to interpret and analyze parametric views in physics problems.
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  • Research the mechanics of wind turbines and their operational principles.
  • Study the applications of kinetic energy equations in fluid dynamics.
  • Explore the concept of reverse windmills and their relevance in physics.
  • Learn about parametric equations and their use in analyzing motion in physics.
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This discussion is beneficial for physics students, educators, and anyone interested in the mechanics of wind energy systems and the application of motion equations in real-world scenarios.

Kamran_110
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Homework Statement


Consider a turbine which actuates the windmills by blowing air into it. (If we use beat steady windmills (which is called reverse windmills) instead of movable windmills, deliberate the following conditions by parametric view. (Ignore the friction power (force))
A. Compare moving speed of air molecules in the following conditions:
1. There are reversed steady windmills between movable windmills.
2. There are movable reversed windmills in the middle of movable windmills which are actuated by wind power (energy).

Homework Equations


I am not sure
E = ½mv2
W = Fd
mv22 = ½mv12
v2 = v02 + 2as
a
= ( v2 - v02 ) / 2s
F
= ma = m ( v2 - v02 ) / 2s
K
= 0.5mv2
Wtot = K2 - K1 = ΔK

The Attempt at a Solution


I do not know
 
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Can you ask your professor for some clarification or guidance in the right direction?
 
scottdave said:
Can you ask your professor for some clarification or guidance in the right direction?

Ok dear friend
 
Kamran_110 said:
beat steady windmills (which is called reverse windmills

Kamran_110 said:
movable windmills

Kamran_110 said:
movable reversed windmills
Can you shed any light on what these terms mean? I can find no matches in a Google search.

Edit: that wasn't quite true. I got lots of matches on "reverse windmill", as a particularly flamboyant way to score in basketball.
 
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Kamran_110 said:
Ok dear friend
I just meant that it appears that you don't know where to start - your description is vague, then you have several formulas that have to do with motion and force and kinetic energy.

So far, nobody here is familiar with this particular terminology, so I thought a fellow classmate or your prof might be able to shed more light that we can (right now, at least).

This forum is great for helping you along in the right direction, but we need to understand more about this problem before we can do that.