Question about acetic acid buffer solutions

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Discussion Overview

The discussion revolves around the behavior of acetic acid buffer solutions when sodium hydroxide (NaOH) is introduced. Participants explore the relationship between hydroxide ions (OH-) and acetic acid (COOH), the calculation of pH after neutralization, and the effectiveness of buffers under varying conditions.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant questions whether OH- immediately reacts with COOH upon the addition of NaOH and discusses the implications for pH calculation.
  • Another participant asserts that neutralization can generally be assumed to go to completion for buffer solutions, with some caveats regarding pH proximity to pKa.
  • A later reply suggests that while a pH difference of 1.82 from pKa is acceptable for NaOH, it may be beneficial to consider alternative buffers for better effectiveness.
  • One participant mentions the importance of using the activity of hydronium ions rather than just molarity when calculating pH changes.
  • Another participant expresses a preference for manual calculations but acknowledges the utility of online calculators for verification.

Areas of Agreement / Disagreement

Participants generally agree on the completion of neutralization in buffer solutions, but there is no consensus on the optimal conditions for buffer effectiveness or the best methods for pH calculation.

Contextual Notes

Participants note that the effectiveness of a buffer is influenced by its proximity to the pKa and that assumptions made in calculations may not hold in all scenarios, particularly for concentrated buffers.

Who May Find This Useful

This discussion may be useful for students and practitioners in chemistry or related fields who are interested in buffer solutions, pH calculations, and the behavior of weak acids and bases in solution.

mesa
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I want to make sure I understand the relationship between OH- and COOH properly.

So if the NaOH is introduced into a buffer solution of acetic acid and it dissociates does the OH- (due to it's very electronegative nature) immediately rip off the H+ from the COOH? If I want to calculate pH do I just subtract the mols of NaOH from mols CH3COOH then calculate the pH from the remaining acetic acid (in molarity) and it's corresponding Ka (1.75X10^(-5))?
 
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Yes, when dealing with buffers you can assume neutralization went to completion (and was stoichiometric). In some specific cases that's not exactly true, but as long as the pH calculated is less than 1 (or even 2) pH units from pKa, you are usually on the safe side.
 
Borek said:
Yes, when dealing with buffers you can assume neutralization went to completion (and was stoichiometric). In some specific cases that's not exactly true, but as long as the pH calculated is less than 1 (or even 2) pH units from pKa, you are usually on the safe side.

Good deal, interesting stuff to think about.
So the cutoff for being able to do this is not clearly defined. It would be fun to play with one of the schools pH meters and explore this further. For what I am doing the difference is 1.82 pH units from pKa, within range for NaOH correct?

So for a weak base do we calculate mols OH- produced using it's corresponding Kb and subtract that from the calculated H+ mols then take the -log of the new molarity of H30+?
 
For not to concentrated buffers it is not difficult to test these things just by calculating pH of the solution, although I would not use Henderson-Hasselbalch equation but a full approach, compare http://www.chembuddy.com/?left=pH-calculation&right=toc. Alternatively, you can use one of my pH calculators for calculations - either BATE or the one built in Buffer Maker (there are free 30-days trials).

1.82 pH unit from pKa for acetic acid - can work, although if you need it to buffer the solution I would look for another buffer. The closer to the pKa you are the more effective the buffer is (the higher is its buffering capacity).
 
That is a good website, interesting how it is not actually the molarity but the activity of the hydronium that is really changing the pH. No surprise that there is still a fairly strong correlation of course.

I like doing this kind of stuff pen to paper but your online calculators would be good to check if I am getting it right until I get more comfortable.

Very helpful.
 

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