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Question about black holes and graviational singularities.

  1. Mar 8, 2010 #1
    Do we know the magnitude of gravitational force needed to violate the Pauli exclusion principle?

    Also, I my research has told me that violating the principle still isn't enough to turn the fallen star into a black hole. It could still become a neutrons star, so if that is the case, what magnitude of force is strong enough squeeze all matter around it to a gravitational singularity which is infinitely dense, with zero volume?

    Also, I have been thinking. Does a black hole necessarily need to be a collapsed gravitational singularity. Couldn't it just have enough mass for light not to escape it?
    Last edited: Mar 8, 2010
  2. jcsd
  3. Mar 9, 2010 #2


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    You won't violate it. It sais that the higher the density, the higher the energy of each particle, thus the higher the pressure. Pressure becomes significant in neutron stars, I'd guess (may be some orders of magnitude off) it's about 10^28 bar at the core.
    You just have to put enough matter in a small enough volume. You'd have to compress a small amount of matter much stronger that a larger mass to generate a black hole.
    When light can't escape, matter must move inwards, as inevitably as it moves towards future.
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