Question about Elastic force and Buoyancy force

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SUMMARY

The discussion centers on calculating the elastic force of a spring connected to a wooden cube submerged in water. The wooden cube has a side length of 10 cm and a density of 0.6 g/cm³, while the water has a density of 1 g/cm³. The correct elastic force is determined to be 4N, derived from the buoyancy force of 10N minus the weight of the cube, which is 6N. The confusion arises from misinterpretations of buoyancy and weight relationships in the context of the problem.

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MatinSAR
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Homework Statement
Elastic force and Buoyancy force
Relevant Equations
Archimedes' principle
Suppose a wooden cube with a side of 10 cm is connected to the bottom of a water container by a spring. If the density of wood is 0.6g/cm^3 and the density of water is 1g/cm^3 , what is the elastic force of the spring? Is it 4N or 6N ?

I think the answer is 4N … But the book says it is 6N , Could you please guide me which one is correct ?!

My answer : Spring force = Buoyancy force - Weight of the cube = 10N - 6N = 4N
 
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MatinSAR said:
My answer : Spring force = Buoyancy force - Weight of the cube = 10N - 6N = 4N
Your thinking looks good to me. (Did the book provide a solution or just the answer?)
 
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Doc Al said:
Your thinking looks good to me. (Did the book provide a solution or just the answer?)
Thank you for your answer.
It said the Spring force is equal to the Buoyancy force that acts on wooden cube and this Buoyancy force is equal to the weight of the cube due to complete submersion in water …
 
MatinSAR said:
... this Buoyancy force is equal to the weight of the cube due to complete submersion in water …
Something is not correct about this last statement.
The weight of what cube?
 
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Lnewqban said:
Something is not correct about this last statement.
The weight of what cube?
We have only one wooden cube in the question and the weight of the cube is 6N.
 
MatinSAR said:
It said the Spring force is equal to the Buoyancy force that acts on wooden cube
That's not right. (It ignores the weight of the cube.)
MatinSAR said:
and this Buoyancy force is equal to the weight of the cube due to complete submersion in water
That's also not quite right (as @Lnewqban points out).

What book are you using?
 
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MatinSAR said:
We have only one wooden cube in the question and the weight of the cube is 6N.
There was a heavier cube originally ocupying the volume of our unique and now submerged wooden cube.
 
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Doc Al said:
That's not right. (It ignores the weight of the cube.)
Thank you …
Doc Al said:
What book are you using?
It's not a reference book like Fundamentals of Physics or …
It was a kind of school book for being ready for the tests and exams …
Lnewqban said:
There was a cube originally ocupying the volume of our unique and now submerged wooden cube.
I'm sorry but I don't understand … Do you mean 6N is false ?!
 
MatinSAR said:
... I'm sorry but I don't understand … Do you mean 6N is false ?!
Please, see:
https://en.m.wikipedia.org/wiki/Buoyancy

The buoyancy effect is generated by the weight of the fluid that has been displaced by the volume of the fully submerged wooden cube.
The fluid surrounding the solid is puting pressure on it, trying to regain that volume.

Think of the cube as a piston of wood pushing down and a piston of water pushing up, only that harder, in the same ratio in which the densities of water and wood differ.

It is only about the statement of post # 3 above, your answer is good.
 
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Lnewqban said:
It is only about the statement of post # 3 above, your answer is good.
Thank you.
 
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