What Is the Correct Calculation for Induced EMF in This Circuit Scenario?

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SUMMARY

The correct calculation for induced EMF in the discussed circuit scenario is 6V for the second loop and 3V for the first loop, leading to a total induced EMF of 6.6V when considering both loops. The current through the circuit is calculated as 0.6A, resulting in a voltage drop of 0.6V across R1 and 6V across R2. The discussion highlights the importance of accurately interpreting circuit diagrams to avoid miscalculations.

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alan123hk
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TL;DR
Interesting and seemingly tricky question about induced electromagnetic force
I think the answer to the first question is 3V and the answer to the second question is 6V
Does anyone have a different answer?
 
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How come you found this one and not the

PS
seemingly tricky question
seemingly :rolleyes: ?

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BvU said:
How come you found this one and not the ...

To be honest, when I started this discussion topic, I didn’t know that another video already showed the answer.

However, Youtube’s artificial intelligence quickly sent this video to my computer screen, I have watched it, but I am sorry, I may be wrong, but I really disagree with the answer provided by the professor, and I just posted my comment below the video.
 
alan123hk said:
and I just posted my comment below the video.
So how about you post your reasoning here in YOUR thread so that we all don't have to go searching elsewhere
 
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davenn said:
So how about you post your reasoning here in YOUR thread so that we all don't have to go searching elsewhere

Because everyone has their own reasons and answers, I hope to give everyone time to think in their own way. When they see answers provided by others (not necessarily including the reasoning process), they may reconsider their reasoning. In addition, maybe many people (including myself) are not 100% sure that their answers are correct, so it is understandable that in this case, people may be patient and not rush to tell the details.

But you are also right. On the other hand, no one seems interested in providing answer so far. I might as well talk about my reasoning as follows,

Since the EMF of one loop is equal to 0.3+3=3.3V, the EMF of the two loops is twice, that is 6.6V, so the current of the two turns closed loop is equal to 6.6V/ (1 + 10) ohm = 0.6A, so the voltage across R1 becomes 0.6A*1 ohm = 0.6V , and the voltage across R2 becomes 0.6A * 10 ohms = 6V. :smile:
 
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Close but wrong. On several counts. Sit out the spoiler -- it really is no punishment.
 
BvU said:
Close but wrong. On several counts.
Thanks for the hint, I got it wrong. Instead of looking at the circuit diagram carefully, I built another circuit structure in my mind for reasoning. :oops:

Take a closer look at the original circuit diagram, the induced EMF of the newly added loop is just superimposed on the original V2.

Circuit.jpg
 
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