- #1

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If G is a group which contains some g of finite order, then by definition g^k=e for some integer k. Does this mean that each element of finite order in G can be written as the generator of some some cyclic subgroup of G?

- Thread starter epr2008
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- #1

- 44

- 0

If G is a group which contains some g of finite order, then by definition g^k=e for some integer k. Does this mean that each element of finite order in G can be written as the generator of some some cyclic subgroup of G?

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