Question about particle reaction

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    Particle Reaction
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The reaction N + ν_e → e^- + P is indeed possible as it conserves charge, baryon, lepton, and fermion numbers, and is a type of charged-current neutrino scattering that neutrino detectors aim to observe. However, for free neutrons, natural decay is more likely unless subjected to a very high neutrino flux. The discussion highlights confusion regarding the implications of charge and parity violations in weak interactions, particularly concerning the existence of right-handed antineutrinos in the Standard Model. It is clarified that while C and CP violations do not render the process impossible, they affect its frequency and angular dependence. Overall, the conversation emphasizes the complexities of particle interactions and the importance of understanding symmetry principles in particle physics.
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It's an easy question, let's consider this reaction:
##N+\nu_e \rightarrow e^{-}+P##
Is this reaction possible? If is not, what does violate?

(I think is possible because charge is conserved, baryon, lepton and fermion numbers are conserved. But I'm not totally sure)
 
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Yes, this is charged-current neutrino scattering. It's one of the processes that neutrino detectors look for.
 
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Yes.

However, note that for free neutrons, it is much more likely that the neutrons will decay naturally unless you have an outrageously high neutrino flux.
 
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Thank you all!
dukwon said:
It's one of the processes that neutrino detectors look for.
I suppose that the cross section it's really small ...
 
Clear Mind said:
Thank you all!

I suppose that the cross section it's really small ...

This is why neutrino detectors are really big ... :)
 
From a few day I've started to study particle physics, so I'm still a little bit confused ... I was wondering:
##N+\nu_e \rightarrow e^{-}+P##
it's a weak interaction, so it should violate c-symmetry, thus:
##\bar{N}+\bar{\nu_e} \rightarrow e^{+}+\bar{P}##
shouldn't be possible ...
I'm a little puzzled :(
 
It is possible if you make both a charge inversion and a parity operation, since the weak force couples to left-handed fermions and right-handed antifermions.

Usually when we talk about an antiparticle it's the CP-conjugate rather than the C-conjugate.
 
yes it is impossible, because you turned a right-handed neutrino into a right-handed antineutrino ... which doesn't exist [in SM]
 
ChrisVer said:
yes it is impossible, because you turned a right-handed neutrino into a right-handed antineutrino ... which doesn't exist [in SM]

It's the other way round. Antineutrinos have to be right-handed in the Standard Model.
 
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ChrisVer said:
yes it is impossible, because you turned a right-handed neutrino into a right-handed antineutrino ... which doesn't exist [in SM]
Right! i was considering only charge, baryon, lepton and fermion numbers but not the parity :s
 
  • #11
dukwon said:
It's the other way round. Antineutrinos have to be right-handed in the Standard Model.

OMG! indeed! Well I'm always forgetting the a-priori left and right... [except for when I write the doublets]...
 
  • #12
C and CP violation do not mean the process is completely impossible. It can have a different dependence on the relative angles (P violation), or occur a bit more or less frequent even with an additional P transformation (CP violation), but it is still possible.
 

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