Question about resistances please

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Homework Help Overview

The discussion revolves around the classification of resistances in a circuit, specifically whether certain resistors are in series or not. The original poster questions the arrangement of a 1-ohm and a 3-ohm resistor, seeking clarification on their connection based on the definition of series resistances.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definition of series resistances and question the presence of branches in the circuit. Some express confusion over the solution provided, while others suggest that the arrangement may not conform to series rules due to the presence of branches at points "a" and "b".

Discussion Status

There is an ongoing exploration of the circuit's configuration, with some participants affirming that the resistors are in series, while others challenge this view based on the circuit's behavior when a voltage or current is applied. The discussion reflects a mix of interpretations regarding the arrangement and the implications of equivalent resistance.

Contextual Notes

Participants note that the original problem does not include a voltage source and focuses on proving the equivalent resistance between points "a" and "b". There is mention of needing to consider transformations or Kirchhoff's laws for analysis, indicating that assumptions about the circuit's configuration are under scrutiny.

carlos125
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Homework Statement



just a questiion aren't the 1-ohm resistance(upper left) and the 3-ohm resistance in series? . The definition for resitance in series is "Two or more elements are in series if they are cascaded or connected sequentially " ,aren't they sharing the same wire? so why aren't they in series?the wire I'm talking about doesn't separate in two branches too , I'm confused
look:View attachment 54025
thanksssss
 
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Yes, they are in series. The 1Ω and 5Ω connected at "b" are also in series.
 


lewando said:
Yes, they are in series. The 1Ω and 5Ω connected at "b" are also in series.

Hi tahnks for your reply well i don't think they are in series because in the solution they don't use the rules of resistances in seires or parallel to solve the problem .check it out
sdfgf.jpg
. but i need to know why . if someone knows please explain
 
Thanks for adjusting the problem statement :smile:. When you apply a voltage across a and b or a current through a and b, then there is a branch at a and at b, so they are not in series.
 
lewando said:
Thanks for adjusting the problem statement :smile:. When you apply a voltage across a and b or a current through a and b, then there is a branch at a and at b, so they are not in series.

actually the original figure doesn't show that the branch at point "a" bifurcates. it only appears in the solution , but i guess i finally get it , i think it's because black dots (nodes) mean that there is always a bifurcation . now everything makes sense , thanks !
 
I read your original post literally. In my mind, a dot is a dot. To be more clear, show the attached voltage/current source. Then the branches will stand out. Glad you are clear!
 
lewando said:
I read your original post literally. In my mind, a dot is a dot. To be more clear, show the attached voltage/current source. Then the branches will stand out. Glad you are clear!

haha there is no a voltage source in this problem, the problem just say that we have to prove that equivalent resistance between "a" and "b" is 27/17 ohm.That's it. :smile:
 
Well something was applied to inject a current, I, into a and outfrom b. Again, resulting in branches, therefore no series resistance.
 
Last edited:
carlos125 said:
haha there is no a voltage source in this problem, the problem just say that we have to prove that equivalent resistance between "a" and "b" is 27/17 ohm.That's it. :smile:
If you consider what is meant by "equivalent resistance", then it is implied that you are finding what resistor could be placed between a & b and provide the same resistance to current flow as the given set of resistors. In other words, it's implied that there is a potential difference applied across a & b and an equivalent resistor would allow the same current to flow as given set of resistors.

This set of resistors cannot be analyzed on the basis of series/parallel analysis, unless you first do Y-Delta transformation.

The other common way to solve this is with Kirchhoff's circuit laws .
 
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