Calculate the total resistance of the circuit

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Homework Help Overview

The problem involves calculating the total resistance in a circuit with resistors arranged in a specific configuration. The original poster expresses difficulty in identifying the arrangement of resistors, particularly regarding a diagonal wire that complicates the analysis.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the flexibility of wires in the circuit diagram and how this affects the identification of nodes. There is a focus on understanding the configuration of resistors after visualizing the contraction of the diagonal wire. Questions arise about whether the resistors are in series or parallel based on their connections.

Discussion Status

Participants are actively engaging with the problem, exploring different interpretations of the circuit layout. Some guidance has been provided regarding the movement of components and the implications for node connections. The discussion is ongoing, with participants seeking clarification on the arrangement of resistors.

Contextual Notes

There is a mention of imposed homework rules regarding the analysis of the circuit, and participants are working within these constraints to understand the setup better.

agoogler
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Homework Statement


Here is the circuit -
0idTL.png


Calculate the total resistance between A and B. ( All resistance are in ohms)

Homework Equations



-

The Attempt at a Solution



The wire which runs across the diagonal from upper left to lower right WITHOUT crossing the other diagonal wire is the thing of problem for me. I can't detect any resistors in parallel or series ! What should I do? Please help !
 
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You can move the components around in the drawing so long as you don't change any of the connections (what's connected to what). Wires can be considered flexible, extendible, and contractible. Any contiguous wire path is the same node, and you can move the connections to that node around as much as you like. So...

That diagonal wire connects the bottom right corner to the top left, which makes it the same node. Call it node A, since terminal A connects there. Suppose you now think about what would happen if that diagonal wire were to contract, pulling the bottom right corner up to the top left corner. How does the circuit look now?
 
gneill said:
You can move the components around in the drawing so long as you don't change any of the connections (what's connected to what). Wires can be considered flexible, extendible, and contractible. Any contiguous wire path is the same node, and you can move the connections to that node around as much as you like. So...

That diagonal wire connects the bottom right corner to the top left, which makes it the same node. Call it node A, since terminal A connects there. Suppose you now think about what would happen if that diagonal wire were to contract, pulling the bottom right corner up to the top left corner. How does the circuit look now?
Now that is a good hint !
Let me redraw -
gCpeZ.png

But now the two 10 ohm resistors are in series or parallel?
 
agoogler said:
Now that is a good hint !
Let me redraw -
gCpeZ.png

But now the two 10 ohm resistors are in series or parallel?

Are both ends of each pair tied together, or only one end of each resistor?

attachment.php?attachmentid=59831&stc=1&d=1372172162.gif
 

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gneill said:
Are both ends of each pair tied together, or only one end of each resistor?

attachment.php?attachmentid=59831&stc=1&d=1372172162.gif
Great so they are in parallel so both evaluate to 5.
Then the top one is in series with the 10 ohm one. So 5+10 =15 ohm which is in parallel with 5 ohm so answer = 5*15/20=75/20=15/4 which is the correct answer!
Thanks a lot ! PF is awesome.
 

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