Question about Thermal Energy Transfer

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SUMMARY

The discussion centers on calculating the mass of a silver block submerged in water, utilizing the principles of thermal energy transfer. The initial temperature of the silver block is 58.5°C, and it is placed in 100.0 g of water at 24.8°C, reaching thermal equilibrium at 26.2°C. The heat transfer equation, q = M x Cs x ΔT, is employed to derive the mass of the silver block, resulting in a calculated mass of approximately 77.5 grams. The calculations were confirmed by another participant, who arrived at a similar result of 77.1 grams, validating the method used.

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  • Familiarity with specific heat capacity (Cs) calculations
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  • Knowledge of thermal equilibrium concepts
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Mr. College
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Homework Statement



A silver block, initially at 58.5* C is submerged into 100.0 g of water at 24.8* C, in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 26.2* C. What is the mass of the silver block?

Homework Equations



q = M x Cs x Δ T

1/M = Cs x ΔT/ q

The Attempt at a Solution



So I'm fairly sure this is right, but want to make sure I didn't get lucky. This question is pretty complex for my first one in the HW. So I decided that I'd rearrange the formula to find the heat and put the search for M. When I did this I found out I had all the variables for this except heat, so I calculated the heat of water with (100g x 4.18 x 1.4) then I plugged that into the equation 1/m = .235 SH x 32.3 *C/585.2 and when I got that answer I put it over one and came up with 77.5 grams of silver

Thoughts? Easier way to do it?
 
Last edited:
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looks good. I get the same answer (well, maybe with a small error due to calculation, I got 77.1, but it's pretty close to yours). And I can't think of any easier way to do it. I think you have done it the way that they expect you to. Nice work, man.
 

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