(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Heated iron with mass of 55.0 g was added to 100 mL of water at 20 degree Celsius. Assuming no energy transfer to the surroundings and that the final temperature of the system is 42.7 degrees C, calculate initial temperature of the iron.

Mass of Iron = 55.0 g

mass of Water = 100g

initial Temp of Water = 20 degrees C

Final temp of Water/Fe = 42.7 degrees

Want: initial temp of Fe

Given Cs of Fe = 0.451 J/gC

Cs of Water = 4.184 J/gC

2. Relevant equations

heat of Iron = -heat of water (q=-q)

mCT = mCT

3. The attempt at a solution

mCT of Fe = -mCT of water

plug in:

X= initial temp of Fe

55 * 0.451*(42.7-X) = 100*4.184*(42.7-20)

When i solve for X , i get a large negative number = -9497.68 which is clearly not the final temperature!

Was wondering where i went wrong!

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# Homework Help: Specific Heat Problem (did something wrong?)

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