Question about thermodynamics (heat loss)

In summary, The problem involves calculating the power needed for an air conditioner in a poorly insulated house with a thermal conductivity of 1.3 W/m·K and an outside temperature of 308K. Using the equation dQ/dt = ak(dT/dx), it can be calculated that the air conditioner will require 16380 W to maintain a temperature of 293K.
  • #1
vande060
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Homework Statement


Suppose that you own a poorly insulated small house, with outside walls l = 0.25m thick, total outer wall plus roof
surface area 210m^2 (about 1992 ft^2) and your walls have a thermal conductivity of 1.3 W/m·K (limestone). Calculate
how much power your air conditioner will require to keep your house at 293K when the outside temperature is 308K.

Homework Equations



maybe dQ/dt = ak(dT/dx)

The Attempt at a Solution



i think

(1.3)(210)(15/.25) = 16380 W

but what do you think? have i made errors?
 
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  • #2
This is a classic 'Carnot refridgerator' problem...

EDIT: Maybe this will help.

http://www.ohio.edu/people/piccard/phys202/carnot/carnot.html

Find an expression for the heat leakage first(through the walls).
 
Last edited:

1. What is thermodynamics and how does it relate to heat loss?

Thermodynamics is the branch of physics that deals with the relationships between heat, work, energy, and temperature. It is the study of how energy is transferred and transformed. Heat loss is a thermodynamic process that occurs when heat energy is transferred from a warmer object to a cooler object.

2. How does heat loss occur?

Heat loss occurs through three main processes: conduction, convection, and radiation. Conduction is the transfer of heat through a solid material. Convection is the transfer of heat through a fluid, such as air or water. Radiation is the transfer of heat through electromagnetic waves, such as infrared radiation.

3. What factors affect heat loss?

There are several factors that can affect heat loss, including the temperature difference between the two objects, the surface area of the objects, the type of material the objects are made of, and the presence of insulation or barriers that can slow down the transfer of heat.

4. How can we reduce heat loss?

There are a few ways to reduce heat loss, including adding insulation to walls, windows, and doors, sealing any air leaks, and using energy-efficient heating systems. It is also important to maintain a constant temperature inside the space to minimize fluctuations and prevent excessive heat loss.

5. What are some practical applications of understanding thermodynamics and heat loss?

Understanding thermodynamics and heat loss is crucial in many industries, such as HVAC (heating, ventilation, and air conditioning), building construction, and energy conservation. It also plays a significant role in everyday life, from cooking food to keeping our homes warm in the winter and cool in the summer.

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