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Question About Torque and Stepping Motors

  1. Mar 4, 2015 #1
    I'm looking for a high torque stepping motor for a project.


    How do I calculate much mass this can move ?

    1.2 N-m = 1.2 J = Force ⋅ Distance = 1.2 kg⋅m2/s2

    Does this mean it has the energy to move 1.2 kg, 1m, in 1 second?

    I'd believe that, but 120 kg, 1m, in 1 second seems way too good so I'm wondering what I'm not thinking about here...
     
  2. jcsd
  3. Mar 4, 2015 #2
    For example, let's say that you connect to the motor axis a wheel of radius ##R##. This wheel pulls a rope at which is commented your mass ##M##, which you have to lift vertically by going against gravity ##g##. Then ##M_{\text{max}} = \dfrac{\tau}{g R}##, where ##\tau## is the output torque of the motor.

    If you just have to move the mass horizontally you have to take into account the friction force of the plane, and solve ##\mu M_{\text{max}} R = \tau##, where ##\mu## is for example the kinetic friction coefficient of your surface, which usually you do not know.
     
    Last edited: Mar 4, 2015
  4. Mar 4, 2015 #3
    Thank you very much.
     
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