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Greg

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$$\left[M\dfrac{\partial}{\partial M}+\beta(g)\dfrac{\partial}{\partial g}+n\gamma\right]G^{(n)}(x_1,x_2,\dots,x_n;M,g)=0$$

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I like Serena

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$$\left[M\dfrac{\partial}{\partial M}+\beta(g)\dfrac{\partial}{\partial g}+n\gamma\right]G^{(n)}(x_1,x_2,\dots,x_n;M,g)=0$$

Hi 1equals1! Welcome to MHB! ;)

$M$ is pronounced as /em/. :p

$\dfrac{\partial}{\partial M}$ is pronounced as /the partial derivative with respect to M/.

$\beta(g)$ is pronounced as /the beta function of g/.

$\gamma$ is pronounced as /gamma/.

$G^{(n)}(x_1,x_2,\dots,x_n;M,g)$ is pronouned as /the n-point correlation function G of $x_1$ up to $x_n$ with parameters M and g/.

I don't know how one pronounces $Callan-Symanzik$.

Perhaps someone who is Russian or Polish or some such would know. :p

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