- #1
Seydlitz
- 262
- 4
Suppose I have this operator:
##D^2+2D+1##.
Is the ##1## there, when applied to a function, considered as identity operator?
Say:
##f(x)=x##.
Applying the operator results in:
##D^2(x)+2D(x)+(x)## or ##D^2(x)+2D(x)+1##?
If ##1## here is considered as an identity operator then the answer will be the former, and the whole operator is linear. But if it's the former, I don't see why the operator will be linear because of the extra ##1## term.
##D## refers to ##\frac{d}{dx}##, and the power of it refers to the order of the derivative.
##D^2+2D+1##.
Is the ##1## there, when applied to a function, considered as identity operator?
Say:
##f(x)=x##.
Applying the operator results in:
##D^2(x)+2D(x)+(x)## or ##D^2(x)+2D(x)+1##?
If ##1## here is considered as an identity operator then the answer will be the former, and the whole operator is linear. But if it's the former, I don't see why the operator will be linear because of the extra ##1## term.
##D## refers to ##\frac{d}{dx}##, and the power of it refers to the order of the derivative.
