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i got this equation
y'=1+x-y
i got y=x+(1-c)
for the isocline c=-1
i got tangent lines which are perpendicular
for c=0 the are not
why is that??
how do i find the slope of each isocline?
y'=1+x-y
i got y=x+(1-c)
for the isocline c=-1
i got tangent lines which are perpendicular
for c=0 the are not
why is that??
how do i find the slope of each isocline?