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## Main Question or Discussion Point

i got this equation

y'=1+x-y

i got y=x+(1-c)

for the isocline c=-1

i got tangent lines which are perpendicular

for c=0 the are not

why is that??

how do i find the slope of each isocline???

y'=1+x-y

i got y=x+(1-c)

for the isocline c=-1

i got tangent lines which are perpendicular

for c=0 the are not

why is that??

how do i find the slope of each isocline???