Question on emission of electrons

[shar_p]

Homework Statement

Monochromatic light of wavelength 4.5 x 10-7 m will eject electrons from the surface of a
metal with a maximum KE of 3.2 x 10-19 Joules. Will light having a wavelength of 6.8 x 10-7
m also cause emission of electrons from this metal

Homework Equations

E = h.c/lambda
KEmax = E - work function

The Attempt at a Solution

In order for the emission to occur, the E > wo
E = [(6.67x10^-34)(3.0x10^8)]/wavelength
so we can find E for wavelength 4.5x10-7 and for wavelength 6.8x10-7

How do we find wo? (work function)

 

[rl.bhat]

KEmax = E - work function
In the problem, KEmax and E is given. Find work function using the above equation. Compare this work function with the energy of the new wave length.

 

[shar_p]

E = [(6.67x10^-34)(3.0x10^8)]/4.5x10^-7 = 4.446x10-33
since KE = 3.2x10^-19, wo = -3.2x10^-19

Enew = [(6.67x10^-34)(3.0x10^8)]/6.8x10-7 = 2.94 x 10^ -33
since wo is negative, though mag of E is smaller than Wo, E > wo and so there will be emission.

I got these answers but the answer specified in the book is E = 2.9x10^-19 and wo = 1.22x10-19 which I didn't get... any ideas what I am doing wrong?

 

[rl.bhat]

E = [(6.67x10^-34)(3.0x10^8)]/4.5x10^-7 = 4.446x10-33
In this the calculation power is wrong. It should be (-34 + 8 + 7) = ...?

 

[shar_p]

Thanks. Since the wo is the same for the metal the one found in 1st case can be used in the 2nd case. Thanks much.