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Question on Lithium-6 superfluidity

  1. May 13, 2013 #1
    Li-6 atom is a fermion gas because it has an odd number of fermion entities: 3 P, 3 N, 3 e- = 9. It also has been reported that Li-6 shows superfluid behavior (wee wiki for superfluidity).

    My question is, would superfluidity behavior be predicted for Li-6 if the three electrons (e-) were removed, making the remaining Li-6 nucleus a boson with even number of fermion entities, e.g., 3 p + 3 N = 6. Has this experiment been conducted ? Thanks.
  2. jcsd
  3. May 13, 2013 #2


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    Staff: Mentor

    You won't be able to form a fluid out of ions: the electrostatic repulsion is too strong.
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