Que- A uniform chain of length L and mass m is held on a smooth table with one-fourth of its length hanging over the edge. If g is the acceleration due to gravity, find the work required to pull the hanging part on the table. CHECK MY SOLUTION---------AND POINT OUT MY MISTAKE. Weight of the hanging part of the chain=mg/4 Therefore, work done=(mg/4)(L/4) =mgL/16..........Answer I am getting this answer. But the correct answer is mgL/32. Is there any role of center of mass in this question?