Ok, first post.(adsbygoogle = window.adsbygoogle || []).push({});

So I have this question, which goes something like this...

Given

P(A)=0.3, P(B)=0.3, P(C)=0.7

P(AnB^c)=0.2, P(AnC^c)=0.2, P(AnBnC)=0

Find P((AnB)U(AnC))

(Where; n =intersect, U union, ^c = complement.)

Personally my thoughts are..

P(AnBnC)=0. Therefore mutually exclusive.

And then Because probability cannot be negative. I think that leads to P(AnB)=0,P(AnC)=0 & p(BnC)=0.

Which couldnt be right, As that would give P((AnB)U(AnC)) = 0U0 = 0.

My major concern is how do I change P(AnC^c) & P(AnB^c) to something useful!

Thanks!

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# Question with intersects and complements.

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