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**1. Homework Statement**

I just would like to know if I'm using the right procedure to solve these problems.

(a) Suzanne is skiing with a velocity of 18.0 m/s (N30.0 degrees W). What is the (N) component of her velocity vector?

(b) TIm is running cross-country at 6.4 m/s (S) when he completes a wide turn and continues at 5.8 m/s (W). What is his change in velocity?

**2. Homework Equations**

Cos(theta) = adjacent / hypotenuse

velocity = V2 - V1

use of Pythagorean theorum formula

**3. The Attempt at a Solution**

(a) Given:

velocity = 18.0 m/s

30 degrees

Required: Vn

Analysis:

cos(theta) = adjacent/hypotenuse

Cos30 degrees = Vn / 18 m/s

Vn = (18.0 m/s) (Cos30 degrees)

=15.6 m/s

(b) Given:

V1 = 6.4 m/s (E)

V2 = 5.8 m/s W

Required: change in velocity

Analysis: velocity = V2 - V1

=V2 + (-V1)

=V2 - V1

use the pythagorean theorum to determine the magintude of the velocity vector.

V^2 = (5.8)^2 + (6.4)^2

=33.64 + 40.96

=74.6 m^2 s^2

=8.64 m/s

Then determine the direction of the velocity vector.

Tan (theta) = 5.8 m/s / 6.4 m/s =0.91

=tan-10.91

=42.3 degrees

Therfore his change in velocity is 8.64 m/s (S 42.3 degrees W)

Any help is always appreciated.

Thanks

Pharm 89

**1. Homework Statement**

**2. Homework Equations**

**3. The Attempt at a Solution**