Quick diagonalize matrix (row reduce)

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Homework Help Overview

The discussion revolves around the diagonalization of a matrix, specifically focusing on eigenvalues and eigenvectors. Participants are examining the implications of reducing a matrix to reduced row-echelon form (RREF) in the context of finding eigenvectors associated with given eigenvalues.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning whether reducing a matrix to RREF affects the eigenvectors obtained from it. There are discussions about specific eigenvalues and their corresponding eigenvectors, with some participants expressing confusion over discrepancies in results from different sources.

Discussion Status

Some participants have provided insights into the relationship between RREF and eigenvectors, suggesting that the eigenvector remains unchanged despite the transformation. However, there is ongoing confusion regarding the correctness of eigenvectors derived from different methods, indicating that multiple interpretations are being explored.

Contextual Notes

Participants are referencing external resources for eigenvector calculations, which may lead to inconsistencies in results. There is a focus on verifying eigenvectors through substitution into the eigenvalue equation.

Nope
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quick please..diagonalize matrix (row reduce)

Homework Statement



http://www.math4all.in/public_html/linear algebra/chapter10.1.html
10.1.5 Examples: (ii)
this part:

-----------------------------------------------------------------------------------------
april95.gif

are both eigenvector for the eigenvalue λ = 3. Similarly, for λ = 6, since
-----------------------------------------------------------------------------------------

Does it matter if I reduce it to rref?

Homework Equations


The Attempt at a Solution

 
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Nope said:

Homework Statement



http://www.math4all.in/public_html/linear algebra/chapter10.1.html
10.1.5 Examples: (ii)
this part:

-----------------------------------------------------------------------------------------
april95.gif

are both eigenvector for the eigenvalue λ = 3. Similarly, for λ = 6, since
-----------------------------------------------------------------------------------------

Does it matter if I reduce it to rref?
Your question doesn't make much sense. The matrices you show are NOT eigenvectors. In the link you gave, it shows two vectors that are the eigenvectors for the eigenvalue 3.

What do you mean by "reduce it to rref"?
 


oh i I figure it out...
I was just asking
Do I get the same eigenvector (which is 0,1,1) if I
transform
-3,0,0
0,1,-1
0,0,0
to rref

In reduced row-echelon form (RREF), the matrix above is
1 0 0
0 1 -1
0 0 0

The only thing that changed is row 1.
You'll get exactly the same eigenvector from this matrix as from the unreduced one.
 
Last edited by a moderator:


And using this calculator
http://wims.unice.fr/wims/en_tool~linear~matrix.html
I found that
Value Multiplicity Vector
6 1 (0,1,1)
3 2 (1,0,1), (0,1,-1/2)

(1,0,1) and (0,1,1) is right, but (0,1,-1/2) is different to the website , which is (1/2,1,0)
I m confused..
 


Nope said:
And using this calculator
http://wims.unice.fr/wims/en_tool~linear~matrix.html
I found that
Value Multiplicity Vector
6 1 (0,1,1)
3 2 (1,0,1), (0,1,-1/2)

(1,0,1) and (0,1,1) is right, but (0,1,-1/2) is different to the website , which is (1/2,1,0)
I m confused..

It's easy to check. Substitute each of these two vectors (i.e., <0, 1, -1/2> and <1/2, 1, 0> in the equation Ax = 3x. If they both make a true statement, they're both eigenvectors.
 

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