- #1
marcflores
- 38
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Homework Statement
[tex](6x^4-3x^2+x-4) / (2x^2+1)[/tex]
Homework Equations
Relevant equations?
The Attempt at a Solution
Here is my attempt, but I want to make sure that I didn't break any laws by changing the number to be divided by switching the last two terms around by using the commutative law of addition:
[tex][6x^4-3x^2+(-4)+x][/tex] -- is this okay so far?
So, I wrote [tex]2x^2+1[/tex] divided by [tex][6x^4-3x^2+(-4)+x][/tex]
Then I wrote it out like long division (can't find the division symbol in laTex) and here are the steps I took:
[tex](3x^2)(2x^2+1) = 6x^4+3x^2[/tex]
Then, I subtracted the product from the first two terms of the dividend:
[tex](6x^4-3x^2) - (6x^4+3x^2) = -6x^2[/tex]
Carry down the +(-4) from the dividend and I have:
[tex]-6x^2-4[/tex]
Then I multiply the divisor by negative three and subtract the product from [tex]-6x^2-4[/tex]:
[tex](2x^2+1)(-3) = -6x^2-3[/tex]
That leaves me with -1 and I carry down the x from the dividend leaving:
-1 + x
So, my answer is [tex]3x^2-3+\frac{-1+x}{2x^2+1}[/tex]
I just want to know if this is correct or if I was wrong in redistributing the terms in the original dividend. Thanks.