What Is the Monic Greatest Common Divisor of Two Given Polynomials?

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Homework Help Overview

The discussion revolves around finding the monic greatest common divisor of two given polynomials, specifically a = 6x^6 + 12x^5 - 6x^4 - 12x + 12 and b = 3x^4 - 3. The context involves polynomial algebra and the application of the Euclidean Algorithm.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the Euclidean Algorithm and question how to derive a monic polynomial from a common divisor that is not monic. There is also an exploration of factorization and the implications of leading coefficients.

Discussion Status

The discussion is ongoing, with participants providing feedback on attempts and clarifying misunderstandings. Some guidance has been offered regarding the process of obtaining a monic polynomial, but no consensus has been reached on the specific steps to take.

Contextual Notes

There are indications of errors in factorization and a general uncertainty about the process of finding the monic greatest common divisor. Participants express a need for further clarification and exploration of the topic.

auru
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Homework Statement



Find the monic greatest common divisor of two polynomials a = 6x6 + 12x5 - 6x4 -12x +12 and b = 3x4 - 3.

Homework Equations



The Euclidean Algorithm.

The Attempt at a Solution



Applying the Euclidean Algorithm, I have

a = 6x6 + 12x5 - 6x4 -12x +12 = (3x4 - 3)(2x2 + 4x -2) + (6x2 + 6)

b = 3x4 - 3 = (6x2 + 6)(##\frac {1}{2}##x2 - ##\frac {1}{2}##)

Now a monic polynomial has a leading coefficient of degree 1. Here, we have a common divisor of 6x2 + 6 which is not monic. How would I go about finding the monic greatest common divisor.
 
Last edited:
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(6x2 + 6) = 6(x2 + 1)?
Your factorization of b has an error.
 
I have fixed it. I'm still unsure how to find the monic greatest common divisor.
 
auru said:
6x2 + 6 which is not monic. How would I go about finding the monic greatest common divisor.
To minimise your embarrassment, I feel it is best to let you think a bit more about that.
 
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haruspex said:
To minimise your embarrassment, I feel it is best to let you think a bit more about that.

Why would I be embarrassed when I don't initially understand something? It may not be initially obvious to me, hence why I have asked for help.

As it turns out, in the general case I am able to divide the common divisor by a constant to attain the monic.
 

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