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Homework Help: Quick help need with finding the MAGNITUDE of the TORQUE of this wrench

  1. Dec 1, 2012 #1
    Number3Physics.png

    I tried using Frsin θ

    (270.756)(46 cm)sin (68) but I got 11547.86

    And got it wrong...

    And then I tried doing.

    101.426982807+251.040591727 = 352.4 N*m but I got it wrong.

    ^ I don't remember how I did that but it was saved in my notes.

    Help?
     
  2. jcsd
  3. Dec 1, 2012 #2

    Doc Al

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    Staff: Mentor

    You have the wrong F. You used the result from part a, which is a torque.
     
  4. Dec 1, 2012 #3
    (60)(9.81) = 588.6

    588.6(46)sin(68) = 25104.0592??
     
  5. Dec 1, 2012 #4

    Doc Al

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    Staff: Mentor

    Right.
    Check your units. (How did you do part a?)
     
  6. Dec 1, 2012 #5
    I think I changed r to meters

    so...

    588.6(0.46)sin (68) = 251.04 N*m

    And direction would be counterclockwise, right?
     
  7. Dec 1, 2012 #6

    Doc Al

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    Staff: Mentor

    Right.

    No. Which way would the wrench tend to turn? Just look at the diagram and use your common experience.
     
  8. Dec 1, 2012 #7
    clockwise


    thanks!
     
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