- #1

- 295

- 2

I tried using Frsin θ

(270.756)(46 cm)sin (68) but I got 11547.86

And got it wrong...

And then I tried doing.

101.426982807+251.040591727 = 352.4 N*m but I got it wrong.

^ I don't remember how I did that but it was saved in my notes.

Help?

- Thread starter riseofphoenix
- Start date

- #1

- 295

- 2

I tried using Frsin θ

(270.756)(46 cm)sin (68) but I got 11547.86

And got it wrong...

And then I tried doing.

101.426982807+251.040591727 = 352.4 N*m but I got it wrong.

^ I don't remember how I did that but it was saved in my notes.

Help?

- #2

Doc Al

Mentor

- 44,993

- 1,266

You have the wrong F. You used the result from part a, which is a torque.I tried using Frsin θ

(270.756)(46 cm)sin (68) but I got 11547.86

- #3

- 295

- 2

(60)(9.81) = 588.6You have the wrong F. You used the result from part a, which is a torque.

588.6(46)sin(68) = 25104.0592??

- #4

Doc Al

Mentor

- 44,993

- 1,266

Right.(60)(9.81) = 588.6

Check your units. (How did you do part a?)588.6(46)sin(68) = 25104.0592??

- #5

- 295

- 2

I think I changed r to metersRight.

Check your units. (How did you do part a?)

so...

588.6(0.46)sin (68) = 251.04 N*m

And direction would be

- #6

Doc Al

Mentor

- 44,993

- 1,266

Right.I think I changed r to meters

so...

588.6(0.46)sin (68) = 251.04 N*m

No. Which way would the wrench tend to turn? Just look at the diagram and use your common experience.And direction would becounterclockwise, right?

- #7

- 295

- 2

clockwiseRight.

No. Which way would the wrench tend to turn? Just look at the diagram and use your common experience.

thanks!

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