Quick help need with finding the MAGNITUDE of the TORQUE of this wrench

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Homework Help Overview

The discussion revolves around calculating the magnitude of torque using a wrench, with a focus on the forces and angles involved in the calculation. Participants are attempting to clarify their understanding of torque and its components.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are sharing their calculations and questioning the values used for force and distance. There is a focus on ensuring the correct application of the sine function in the torque formula, as well as verifying unit conversions.

Discussion Status

Some participants have provided guidance regarding the correct force to use and the importance of checking units. There is an ongoing exploration of the direction of torque, with participants reflecting on the physical setup and their calculations.

Contextual Notes

There is mention of previous parts of the problem that may influence the current calculations, specifically regarding the values derived from earlier steps. Participants are also considering the implications of unit conversions from centimeters to meters.

riseofphoenix
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I tried using Frsin θ

(270.756)(46 cm)sin (68) but I got 11547.86

And got it wrong...

And then I tried doing.

101.426982807+251.040591727 = 352.4 N*m but I got it wrong.

^ I don't remember how I did that but it was saved in my notes.

Help?
 
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riseofphoenix said:
I tried using Frsin θ

(270.756)(46 cm)sin (68) but I got 11547.86
You have the wrong F. You used the result from part a, which is a torque.
 
Doc Al said:
You have the wrong F. You used the result from part a, which is a torque.

(60)(9.81) = 588.6

588.6(46)sin(68) = 25104.0592??
 
riseofphoenix said:
(60)(9.81) = 588.6
Right.
588.6(46)sin(68) = 25104.0592??
Check your units. (How did you do part a?)
 
Doc Al said:
Right.

Check your units. (How did you do part a?)

I think I changed r to meters

so...

588.6(0.46)sin (68) = 251.04 N*m

And direction would be counterclockwise, right?
 
riseofphoenix said:
I think I changed r to meters

so...

588.6(0.46)sin (68) = 251.04 N*m
Right.

And direction would be counterclockwise, right?
No. Which way would the wrench tend to turn? Just look at the diagram and use your common experience.
 
Doc Al said:
Right.


No. Which way would the wrench tend to turn? Just look at the diagram and use your common experience.

clockwise


thanks!
 

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