Quick question about equilibrium of a reaction

[mjolnir80]

Homework Statement

we have a solution of
Cocl^{}2-_{}4(alcohol) + 6H_{}2O(l) <---> Co(H_{}2+O)_{}6^{}2+(aq) + 4Cl-(aq)
at equilibrium
what would happen if we were to add more H2O?

The Attempt at a Solution

we can't really change the concentration of the water so nothing would happen?

edit: sorry abot the bad reaction formula

 

[eli64]

this is an equilibrium, what happens when one side of the equilibrium is disturbed? what chemical principle is this related to?

 

[mjolnir80]

its related to le chatelires principle but I am not sure whether the water has any effect at all because we can't really change the concentration of the water

 

[eli64]

any reactant or solvent in a chemical reaction has a concentration, even water. So what will the equilibrium do if more water is added?

 

[Borek]

It is hard to tell from your reaction, but isn't it done in alcohol, in which case water concentration can be easily controlled?

 

[eli64]

likely the CoCl2 4- was prepared with an alcohol content in its solution to maintain this species and not revert to the water product.

Homework Statement

we have a solution of
Cocl^{}2-_{}4(alcohol) + 6H_{}2O(l) <---> Co(H_{}2+O)_{}6^{}2+(aq) + 4Cl-(aq)
at equilibrium
what would happen if we were to add more H2O?

water is a reactant here.

 

[chemisttree]

Homework Statement

we have a solution of
CoCl₂^-4(alcohol) + 6H₂O(l) <---> Co(H₂O)₆⁺²(aq) + 4Cl^-(aq)
at equilibrium
what would happen if we were to add more H2O?

Here is a cleaned up version of your equation. Hit 'quote' to see how I did it.

I think it should be:

CoCl₄^-2(alcoholic) + 6H₂O(l) <---> Co(H₂O)₆⁺²(aq) + 4Cl^-(alcoholic)