Quick question about free variables

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Free variables in a system of equations allow for infinitely many solutions, as illustrated by the example provided. In the given system, z is designated as the free variable, enabling the derivation of x and y as dependent variables based on z. The choice of which variable to designate as free is arbitrary; one could also select x as the free variable and express the solutions accordingly. The preference for z in this case likely stems from the simplicity it offers in solving for x and y. Ultimately, any variable can be chosen as free, leading to equivalent solution sets.
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Hopefully I have this in the right place, it's not a homework question exactly, rather a question I have as I'm reading through my text. I'm learning about free variables. The book gives the example system:

x - z = 2
y + 2z = -1
0 = 0

as an example of a system with infinitely many solutions. I see that the way to express the solution set for this system is by describing the line that the solutions lie on. It says to make z the 'free variable' and make x and y the 'dependent' variables. Then by picking z I can find values for x and y that work. This makes sense to me. But why can't I solve for, say, x and z in terms of y? Why do I have to pick z as the free variable?
 
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The free parameter you choose is arbitrary, so just as you could say, like the book, that z is free and then

<br /> (x,y,z)=(2+z,-1-2z,z)<br />

you could also have said that x was your free parameter and stated the solutions as

<br /> (x,y,z)=(x,3-2x,-2+x)<br />

I think they must have chosen z because, in this case, it is easier to solve for x and y.
 
Thanks so much!
 
Anytime!
 
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