Quick Question on mass/spring system

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SUMMARY

The discussion focuses on a mass-spring system with a 3Kg mass oscillating with an amplitude of 0.15m and a period of 2s. The total energy of the system is calculated using the formula (.5)mv^2 + (.5)kx^2 = (.5)kA^2, leading to a spring constant of 29.6 N/m and a total energy of 0.333J. Additionally, the direction of a periodic wave described by the equation 0.15m*sin(10t+(π)x) is confirmed to be positive due to the positive coefficient of (π)x.

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Homework Statement



A 3Kg mass, attached to spring oscillates w/ amplitude of .15m and a period of 2s. At time t= 0.5s the objects position is .019m.

Find the total energy of the system



Homework Equations



(.5)mv^2+(.5)kx^2= (.5)kA^2



The Attempt at a Solution



I found the spring constant to be 29.6 N/m... my only question is this... (.5)mv^2+(.5)kx^2
would give me the answer, as would (.5)kA^2 correct? to get the total energy i just did (.5)(29.6)(.15)^2 = .333J

Is that correct?
 
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Yes it is.
 
rock.freak667 said:
Yes it is.

Thank a bunch rock... i also had one other quick question that i figure ill post here so i don't start another post minutes after this one...

A periodic wave has the equation .15m*sin(10t+(pi)x)

Now i am getting a little bit mixed up about how to determine the direction of the wave... I am going to say this wave is moving in a positive direction because (pi)x is positive... meaning it is going forward... is that correct? So when i rewrite the equation it would be .15m*sin(10t+(pi)(x-vt)) to account for the positive change? Thanks for all of the help guys.
 

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