Quicker Method to Find Taylor Series of sinz - sinhz?

[connor415]

I have to find the first three non zero terms of this series by hand. I know the answer and it is

-(z^3/3) - z^7/2520 - z^11/19958400

Which will take ages to get to by brute force. Is there a quicker way?

 

[tiny-tim]

hi connor415!

but that's just (n!)/2 …

what's brutish about that? ​

 

[connor415]

The method I used was brutish. I didnt use the generalized form of the series for sin and sinh that I think youre referring to. I now am, and its faster. Thanks