MHB Radian Measure: Show Cone Surface Area is $\pi rl$

  • Thread starter Thread starter Sherlock16
  • Start date Start date
  • Tags Tags
    Cone Measure
Click For Summary
A cone's curved surface area can be derived by transforming it into a sector of a circle with radius equal to the slant height, \( l \), and angle \( \theta \). The relationship between the arc length of the sector and the circumference of the cone's base leads to the equation \( l\theta = 2\pi r \). By calculating the area of the sector, which is given by \( \frac{1}{2}l^2\theta \), and substituting for \( \theta \), it can be shown that the curved surface area of the cone is \( \pi rl \). This derivation highlights the connection between the geometry of the cone and the properties of circular sectors. Understanding this relationship is crucial for solving problems involving cone surface areas.
Sherlock16
Messages
1
Reaction score
0
A cone with base radius $r$, vertical height $h$ and slant height $l$ has its curved surface slit and flattened out into a sector with radius $l$ and angle $\theta$. By comparing the arc length of this sector with the circumference of the base of the cone, show that $l\theta = 2\pi r$, and deduce by calculating the area of the sector, that the curved surface area of the cone is $\pi rl$.
 
Mathematics news on Phys.org
Welcome, Sherlock16!

Please show what you've tried or what your thoughts are on this problem, so that we could better assist you.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...