1. The problem statement, all variables and given/known data A lead nucleus contains 207 nucleons (82 protons and 125 neutrons) packed tightly against each other. A single nucleon (proton or neutron) has a radius of about 1 ✕ 10^−15 m. (a) Calculate the approximate radius of the lead nucleus. (b) Calculate the approximate radius of the alpha particle, which consists of 4 nucleons, 2 protons and 2 neutrons. (c) What kinetic energy must alpha particles have in order to make contact with a lead nucleus? 2. Relevant equations v_sphere = 4/3 pi r^3 r_nucleon = 1 * 10 ^ -15 m 3. The attempt at a solution 207 * 1 * 10 ^ -15 m 2.07 * 10 ^ -13 m Beyond this, I don't have any idea what to do. I considered using d = m/v, but stopped halfway because I was approaching a bizarre answer.