Raising and Lowering momentum operators

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SUMMARY

The discussion focuses on the eigenvalues of the raising (L+) and lowering (L-) momentum operators in quantum mechanics. It is established that applying the raising operator L+ to the state |l,m2> yields the eigenvalue multiplied by the state |l,m2+1>. The orthogonality condition indicates that the inner product equals zero unless m1 equals m2+1, which is represented by Dirac delta functions. This relationship is crucial for understanding the action of these operators on quantum states.

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I tried to use the eigenvalue of the operators but I couldn't get the result.
Can anyone help me to understand this relationship?

Thank you.
 
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if you multiply out the brackets inside the square root, you will find that they are in fact the eigenvalues of the L+ and L- operators.

Remember that L+|l,m2> = Eigenvalue*|l,m2+1>

Once you have operated with L+ on the left hand side you can move the eigenvalue out to the front as it is just a number. You are left with:

<l,m1|l,m2+1>, which, by orthogonality, is 0 unless m1 = m2+1. This is precisely what the dirac delta functions on the right hand side represent.
 

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