# Raising and lowering operators acting on spin 1 kets?

1. Dec 17, 2008

### philip041

I read in my notes that

S{-}|1> = sqrt(2)h(bar)|0>

and similar for all six products of using the raising and lowering operators on |1>, |0>, |-1>

I don't understand where the sqrt(2)h(bar) has come from?

Cheers

Philip

2. Dec 17, 2008

### malawi_glenn

$$J_{\pm}|j,m> = \hbar \sqrt{j(j+1) - m(m\pm 1 )}|j,m \pm 1 >$$

3. Dec 22, 2008

### philip041

bo select

4. Dec 23, 2008

Huh?