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Raising and lowering operators acting on spin 1 kets?

  1. Dec 17, 2008 #1
    I read in my notes that

    S{-}|1> = sqrt(2)h(bar)|0>

    and similar for all six products of using the raising and lowering operators on |1>, |0>, |-1>

    I don't understand where the sqrt(2)h(bar) has come from?

    Cheers

    Philip
     
  2. jcsd
  3. Dec 17, 2008 #2

    malawi_glenn

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    [tex] J_{\pm}|j,m> = \hbar \sqrt{j(j+1) - m(m\pm 1 )}|j,m \pm 1 > [/tex]
     
  4. Dec 22, 2008 #3
    bo select
     
  5. Dec 23, 2008 #4

    malawi_glenn

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    Huh?
     
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