Raising both sides of equation to a common base

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Discussion Overview

The discussion revolves around the correct manipulation of logarithmic and exponential equations, specifically focusing on the equation \( \ln|y| = kt + C \). Participants explore the implications of exponentiating both sides and the conditions that arise from this process, including the treatment of constants and the nature of solutions.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants assert that when exponentiating both sides of an equation, the entire left-hand side (LHS) and right-hand side (RHS) must be treated as a whole, leading to the conclusion that \( e^{kt + C} = A e^{kt} \) where \( A = e^C \).
  • Another participant emphasizes the conversion from logarithmic to exponential form, stating that \( \log_a(b) = c \implies b = a^c \).
  • One participant raises a concern regarding the positivity of \( A \), noting that since \( e^C = A \), it implies \( A > 0 \), which should be specified in the final answer.
  • Another participant counters that with the absolute value in the logarithm, \( A \) can be any real number, suggesting that the trivial solution \( y \equiv 0 \) has been eliminated.
  • There is a recognition of the importance of being aware of any restrictions imposed by the manipulations performed.

Areas of Agreement / Disagreement

Participants express differing views on the implications of the constant \( A \) and whether it should be restricted to positive values or can be any real number. The discussion remains unresolved regarding the treatment of \( A \) and the conditions under which the manipulations hold.

Contextual Notes

Participants note the importance of specifying conditions related to the constants derived from exponentiation and logarithmic transformations, highlighting the potential for different interpretations based on the presence of absolute values.

find_the_fun
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I've been doing something very wrong for a long time.
$$
ln|y| = kt+C $$
$$e^{ln|y|}=e^{kt}+e^C $$
$$ y=e^{kt}+e^c$$
which should have been
$$
e^{ln|y|}=e^{kt+C} $$
$$ y=e^{kt} \cdot e^C = Ae^{kt}$$

Is the idea you are operating on the entire RHS and LHS side as a whole?
 
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find_the_fun said:
I've been doing something very wrong for a long time.
$$
ln|y| = kt+C $$
$$e^{ln|y|}=e^{kt}+e^C $$
$$ y=e^{kt}+e^c$$
which should have been
$$
e^{ln|y|}=e^{kt+C} $$
$$ y=e^{kt} \cdot e^C = Ae^{kt}$$

Is the idea you are operating on the entire RHS and LHS side as a whole?

Yes, that is correct. In general we have that if $x = y$ then $f(x) = f(y)$ for any function $f$ (with suitable domain). Hence the entire LHS and RHS must be passed into the function, or it doesn't work. In this case we have:

$$e^{kt + C} = e^{kt} e^C = e^C e^{kt}$$

Where the $e^C$ term can then be thought of as another constant $A = e^C$, giving:

$$e^{kt + C} = A e^{kt}$$

Intuitively, exponentiation turns addition into multiplication, and multiplication into exponentiation. Conversely, logarithms turn exponentiation into multiplication, and multiplication into addition (and addition into... addition. you can't simplify $\log(a + b)$ in general).
 
The way I look at converting from logarithmic to exponential form is to use:

$$\log_a(b)=c\implies b=a^c$$
 
Pet peeve warning! Danger Will Robinson! Danger!

Note that [math]e^C = A[/math] implies A > 0, so you need to specify that when you list your final answer.

End of Pet Peeve.

-Dan
 
topsquark said:
Pet peeve warning! Danger Will Robinson! Danger!

Note that [math]e^C = A[/math] implies A > 0, so you need to specify that when you list your final answer.

End of Pet Peeve.

-Dan

With the absolute value on the argument of the log function, I would say we need not specify a restriction on $A$...also we likely have eliminated a trivial solution $y\equiv0$ and so this can be accounted for by letting $A$ be any real number. :D

However, you do raise a good point...we should be aware of any restrictions we may impose.
 

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