Raman spectroscopy and the phonon confined in the Brillouin zone

In summary, Raman spectroscopy measures the inelastic scattering of a photon in a medium through the absorption or emission of a phonon, with energy and momentum conservation being represented by equation (1). The phonon involved in Raman scattering is limited to the central region of the first Brillouin zone due to the small wave vector of the incoming photon and the quantification of q. This allows for the validity of equation (1) to be maintained. In order to study phonon processes along the full dispersion curve, inelastic x-ray or neutron scattering would need to be used instead.
  • #1
phzrosmary
1
0
Hello everyone,

I need some confirmation on something:

As far as I understood, the raman spectroscopy measures the inelastic scattering of a photon in a medium through the absorption or the emission of a phonon in the medium. The energy and the momentum is conserved.

hk_in=hk_out +- hq (1) Momentum conservation

k_in and k_out being the incoming and the scattered wave vector, and q the impuls of the phonon.
q is quantified.

now the difficulty:

why are the phonon taking part in the raman scattering limited to the central region of the first brillouin zone?

what I think:

the incoming photon has a very small wave vector compared to the dimension of the brillouin zone. q is limited to the central region of zone, otherwise q would be bigger than k_in, and that would violate (1). Is it valid? When would you use the quantified phonon as an argument for the confinement of q in the brillouin zone though?

Thank you very much for your help in advance

peace
 
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  • #2
Raman is effectively a q=0 probe. The photon cannot impart enough momentum to study phonon processes along the full dispersion curve, you need inelastic x-ray or neutron scattering to do that.
 
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1. What is Raman spectroscopy and how does it work?

Raman spectroscopy is a technique used to study the vibrational modes of molecules. It involves shining a laser onto a sample and measuring the scattered light. The resulting spectrum provides information about the chemical bonds and structure of the sample.

2. What is the Brillouin zone and why is it important in Raman spectroscopy?

The Brillouin zone is a mathematical construct used in solid state physics to describe the energy levels of a crystal lattice. In Raman spectroscopy, the phonon modes (vibrational modes) of a crystal are confined within the Brillouin zone, making it a useful tool for studying the crystal's properties.

3. How does Raman spectroscopy help in identifying chemical compounds?

Each chemical compound has a unique Raman spectrum due to the specific arrangement of its atoms and bonds. By comparing the Raman spectrum of an unknown compound to a database of known spectra, it is possible to identify the compound.

4. Can Raman spectroscopy be used to study biological samples?

Yes, Raman spectroscopy can be used to study biological samples such as cells, tissues, and fluids. It can provide information about the molecular composition and structure of these samples, making it a valuable tool in various fields of biology and medicine.

5. What are the limitations of Raman spectroscopy?

Raman spectroscopy is a non-destructive and non-invasive technique, but it does have some limitations. It is not suitable for studying samples that are highly fluorescent or have a low Raman scattering efficiency. Additionally, the technique is sensitive to the orientation of the sample and requires careful sample preparation to obtain accurate results.

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