Raman Spectroscopy: Why Peaks of Stokes Higher than Anti-Stokes?

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SUMMARY

The discussion centers on the phenomenon of Raman spectroscopy, specifically addressing why Stokes peaks are higher than anti-Stokes peaks in absorbance graphs plotted against wave number. The key conclusion is that anti-Stokes scattering occurs when the initial state is an excited state, which has a lower population of electrons compared to the ground state. This results in lower intensity peaks for anti-Stokes compared to Stokes peaks, which originate from the ground state. The relationship between electron population and peak intensity is crucial in understanding this aspect of Raman spectroscopy.

PREREQUISITES
  • Understanding of Raman spectroscopy principles
  • Knowledge of electronic states in molecular systems
  • Familiarity with absorbance and wave number concepts
  • Basic grasp of population distribution in quantum states
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  • Research the principles of Stokes and anti-Stokes scattering in Raman spectroscopy
  • Study the population distribution of electrons in excited and ground states
  • Explore the mathematical modeling of Raman peak intensities
  • Investigate applications of Raman spectroscopy in material science
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Researchers, chemists, and physicists interested in the applications of Raman spectroscopy, particularly in understanding molecular interactions and electronic states.

fricke
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Why do peaks of Stokes higher than peaks of anti-Stokes in graph of absorbance unit against wave number?
 
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Because anti-Stokes typically takes place when the initial state is an excited state.
 
blue_leaf77 said:
Because anti-Stokes typically takes place when the initial state is an excited state.
Thank you for your reply!
So, anti-Stokes has lower peaks than Stokes because its initial state is an excited state where the population of electrons at excited state is lower than the ground state? Does it make sense?
 
fricke said:
Thank you for your reply!
So, anti-Stokes has lower peaks than Stokes because its initial state is an excited state where the population of electrons at excited state is lower than the grounded state? Does it make sense?
Basically yes.
 

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