Rate of change in distance question

Click For Summary

Homework Help Overview

The problem involves calculating the rate of change in distance from home plate for a player running from second to third base on a baseball diamond, with specific distances and speeds provided.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply the Pythagorean theorem and differentiate to find the rate of change of distance from home plate. Some participants suggest simplifying the notation and question the clarity of the differentiation step.

Discussion Status

Participants are engaging with the original poster's approach, providing feedback on the clarity and presentation of the solution. There is no explicit consensus on the correctness of the calculations, but some guidance has been offered regarding simplification.

Contextual Notes

The original poster is working independently and relies on limited resources, which may affect the clarity and presentation of their solution.

Dr Zoidburg
Messages
39
Reaction score
0
Okay, I'm 99% sure I've got the right answer here, but I just wanted to make certain before I send my assignment in. It's the last question and has been bugging me for the last few days until I had an eureka moment just a few minutes back.
(In case you're wondering, I'm doing my studies by correspondence, so other than course notes and textbooks borrowed from the library I have just the internet and my brains (hah!) to aid me)

Homework Statement


A baseball diamond has sides 27m long. A player is running from 2nd to 3rd at a speed of 9m/s. When he is 6m away from 3rd, at what rate is the player's distance from home plate changing at that instant?


The Attempt at a Solution


x = distance from home plate to 3rd = 27m
y = distance from player to 3rd = 6m
z = distance from player to home = 27.66m (using pythagoras)
speed of player is change of y over time: dy/dt = 9m/s

z^{2} - y^{2}= x^{2}
differentiate with respect to time:
d/dzz^{2} - d/dyy^{2}= 0 (since x doesn't change over time)

dz/dt*2z - dy/dt*2y = 0
divide by 2:
z*dz/dt - y*dy/dt = 0
sub the above (z, y, dy/dt) into the equation and solve:
dz/dt = 1.95m/s

If this ain't correct, please tell me quickly as I need to post my assignment off asap!
 
Physics news on Phys.org
Hi Dr Zoidburg! :smile:

Yes, that's fine (but a little messy)! :smile:

Try shortening it a bit.

For example, there's no need to define an x (I know it's useful for helping you get to your eureka moment, but once you're there, you can forget it) … just say z² = y² + 729 (or z = √(y² + 729)). :smile:

And
Dr Zoidburg said:
d/dzz^{2} - d/dyy^{2}= 0
doesn't make sense, does it? :rolleyes:
 
yay, got it right! Off to the post office I scurry.

And that other bit just came out poorly due to bad formating. It looks better in my assignment :wink:
 
Dr Zoidburg said:
yay, got it right! Off to the post office I scurry.

:smile: I thought Dr Zoidburg scuttled ? :smile:
 
whoops. you're right there. scuttled. whoop! whoop! whoop!

"Friends, help! A guinea pig tricked me!"
 
I just did a google search for "A guinea pig tricked me",

:biggrin: and got 5370 hits! :biggrin:
 

Similar threads

Replies
6
Views
1K
Replies
8
Views
1K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K