Rate of EM emission based on surface characteristics

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SUMMARY

The discussion centers on the rate of electromagnetic (EM) emission based on surface characteristics, specifically comparing black painted surfaces and aluminum plates. Participants highlight that dark matte surfaces exhibit higher emissivity, making them better emitters of EM radiation. The conversation references the Stefan-Boltzmann law to analyze the temperature differences between surfaces and their emissivity. Ultimately, the aluminum plate is considered a significant factor due to its higher temperature, raising questions about the balance between emissivity and temperature in determining EM emission rates.

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  • Understanding of emissivity and its impact on thermal radiation
  • Familiarity with the Stefan-Boltzmann law
  • Basic knowledge of black body radiation principles
  • Concept of differential heating in thermal systems
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druscilla
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Homework Statement
Given a scenario where there is a black painted surface at a temperature of 15 degrees Celsius and a polished aluminum plate at 20 degrees Celsius, could you determine which of these objects experiences a higher rate of emission of electromagnetic radiation per unit area?
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I would think the black painted surface is
 
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druscilla said:
I would think the black painted surface is
And, why do you think that ?
 
Since dark matt surfaces are better emitters of em radiation because of higher emissivity
 
You are correct but the fact that it is black to your eye speaks only to its emissivity/absorbance behavior for radiation in the visible spectrum. What is the peak black body emission for ~300K?
Also how are these objects being heated? They will not maintain a temperature difference unless differentially heated.
 
druscilla said:
Since dark matt surfaces are better emitters of em radiation because of higher emissivity
Right, but the aluminium plate is hotter. So the question is, is the temperature difference enough to overcome the emissivity difference? How will you assess that?
hutchphd said:
Also how are these objects being heated? They will not maintain a temperature difference unless differentially heated.
I think we are supposed to assume those temperatures are maintained somehow.
 
No other variables were stated in the question, so now I think the Al plate must be the answer given Stephan-Boltzmann's law
 
druscilla said:
No other variables were stated in the question, so now I think the Al plate must be the answer given Stephan-Boltzmann's law
I see no reason to jump to the opposite conclusion.
If the emissivities were the same, what would the power ratio be?
What emissivity ratio would balance that?
 

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