Rates, whats wrong with my working?

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Discussion Overview

The discussion revolves around calculating the rate constant, k, for the conversion of cyclopropane to propene, which is described as a first-order process. Participants are examining the methodology and results of a specific calculation involving concentration changes over time.

Discussion Character

  • Technical explanation, Debate/contested, Homework-related

Main Points Raised

  • One participant presents their calculation for the rate constant, k, using the formula In[A] - In[A] = -kt, and arrives at a value of 0.011576.
  • Another participant questions the units of the correct answer, suggesting that verification of the units is necessary.
  • A third participant provides the textbook answer of 9.19 x 10-4/s and raises the possibility of an error in the textbook or the formula being used.
  • A later reply expresses uncertainty about the reliability of the textbook, implying that it may not be a recognized source.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct value of the rate constant or the reliability of the textbook answer. Multiple competing views regarding the calculation and potential errors remain unresolved.

Contextual Notes

There is uncertainty regarding the correctness of the formula used and the reliability of the textbook answer, which may affect the validity of the calculations presented.

geffman1
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hey guys I've got a question.

We examine the conversion of cyclopropane to propene, a first order process. If we begin with 0.0200 M cyclopropane and find that after 168 s the concentration of propene is 0.00286 M, what is the rate constant, k, at this temperature?

My working:
In[A]-In[A]=-kt
(In0.00286-In0.0200)/168=-k
therefor k=0.011576 however correct answer is 9.19x10-4

anyhelp would be good. thanks
 
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Hello there,

I get the same answer in mol/(L x s) as you. Could you verify that the correct answer is given in the same units?

Thanks.
 
C. 9.19 x 10-4/s here's the answer out exercise, maybe they just made a mistake, are we using the right formula? thanks for the reply
 
You're welcome.

Unfortunately, I still have not found a different answer. Is this textbook a recognised, leading one in chemistry? If not, then the answer key may be erroneous.
 

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