# Rate Constant Determination - Isolation Method Homework Help Needed

• cvc121
In summary: Anyway, back to the problem. The rate equation is R = k [NO]2. The slope of the graph of [NO] is kobs = k [NO]2. So plugging into the equation R = kobs[O2], we get R = 567.8 M-2s-1. This is the same as the value you got from experiment 1.
cvc121

## Homework Statement

Due to formatting problems, I have attached the problem below.

## The Attempt at a Solution

Plotting the appropriate graphs and based on linearity, I have determined that the reaction is first order with respect to [O2] and second order with respect to [NO]. Therefore, the reaction is third order overall and this corresponds to M-2s-1 as the units for the rate constant, k.

However, I am unsure of how to solve for the rate constant. I know that this is an isolation method problem where the initial concentration of one reactant is much smaller than the initial concentration of the others. As such, the large concentrations barely change during the reaction and are approximately constant.

I also know that I will be needing the slopes of the graphs. For the graph of [O2] in experiment 1, the slope is 0.2328. The slope of the graph of [NO] for the second experiment is 0.0000238.

For instance, in experiment 1, the concentration of NO would stay approximately constant throughout the reaction because it is so large relative to the concentration of [O2]. So I could write the rate constant as R = kobs (observed rate constant - corresponds to slope of the graph) [O2].

Do I just plug in the numbers? Using experiment 1:
k = observed rate constant / [O2] = 0.2328 / 4.10 x 10-4 = 567.8 M-2s-1?

I do not think this is correct because going through the same process for experiment 2, I get a different result.

Can anyone provide some guidance? Thanks. All help is very much appreciated.

#### Attachments

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Compare your equation R = kobs[O2] with the true rate equation. What is kobs equal to?

mjc123 said:
Compare your equation R = kobs[O2] with the true rate equation. What is kobs equal to?

My true rate equation is R = k [NO]2[O2]. Therefore, the observed rate constant, kobs, is equal to k [NO]2. Rearranging this, I get k = kobs / [NO]2. So do I plug the values from experiment 1 into this equation to get the actual rate constant?

k = 0.2328 / [9.63 x 10-1]2 = 0.251 M-2s-1?

Should be. How does it compare with what you get from experiment 2? At least it has the right units, which it would have been obvious your previous attempt didn't, if you had included the units rather than just writing down numbers. I can't emphasise enough the importance of ALWAYS THINKING UNITS, it will save you a lot of trouble and mistakes.

Please show your calculations, and particularly, your calculations of the slopes. Your approach and mjc123's comments are correct. There must be an arithmetic error or units error somewhere. It's hard to help without seeing more details of the calculations (particularly for the 2nd order NO case).

You keep saying 'the slopes' but without saying the slopes of what against what I think.

My first reaction seeing the question was what clever experimenters these homework setters are! They chose their two concentrations and timed their measurements exactly so that at each time the concentration was half of what it was the last time! I expect they did this to enable you to see at first glance the reaction is first order in [O2] which was too obvious for you to mention, but it's not as easy as they make it seem to set up an experiment like that.

## 1. What is the Rate Law - Isolation Method?

The Rate Law - Isolation Method is a technique used in chemical kinetics to determine the rate law of a reaction. It involves isolating a specific reactant and measuring its concentration over time to determine its effect on the rate of the reaction.

## 2. How is the Rate Law - Isolation Method performed?

To perform the Rate Law - Isolation Method, a reactant is isolated by keeping the concentration of all other reactants constant. The reaction is then allowed to proceed and the concentration of the isolated reactant is measured at different time intervals. The data is then used to determine the rate law of the reaction.

## 3. What are the benefits of using the Rate Law - Isolation Method?

The Rate Law - Isolation Method allows for the determination of the rate law of a reaction without the need for complex mathematical calculations. It also provides insight into the individual effects of each reactant on the rate of the reaction.

## 4. How accurate is the Rate Law - Isolation Method?

The accuracy of the Rate Law - Isolation Method depends on the precision of the measurements taken and the validity of the assumptions made. It is important to carefully control the experimental conditions and take multiple measurements to improve accuracy.

## 5. What are the limitations of the Rate Law - Isolation Method?

The Rate Law - Isolation Method may not be suitable for reactions with multiple steps or complex mechanisms. It also assumes that the concentration of the isolated reactant does not significantly affect the concentrations of other reactants, which may not always be the case.

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