Ratio of charges in thomson expt

  • Thread starter ananthu
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Homework Statement



three particles having charges 1:2:3 produce the same point on the photographic film in the thomson experiment. The masses are in the ratio of a) 1:2:3 b)3:2:1 c) 2:3:1 d) 1:3:2

Homework Equations



a = F/m = Eq/m

The Attempt at a Solution



Since all the three particles are striking at the same point on the screen, they should be subjected to same acceleration. Assuming that same electric field acts on all the three particles, then,
q1/m1= q2/m2 = q3/m3 which implies q/m is constant. Hence, q is directly proportional to m. So the masses must be in the ratio of 1:2:3 .

I want to confirm whether this solution is correct. Does this problem contain all the relevant information needed? I will be thankful if any body clarifies my doubt.
 

Answers and Replies

  • #2
gneill
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Presumably the experiment you're referring to involves J.J. Thomson's mass spectrometer? If so then you've reasoned correctly that the charge to mass ratio needs to be the same to produce the same accelerations.
 

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