Ratio of the Magnitude of gravitational force?

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Homework Help Overview

The discussion revolves around calculating the gravitational forces between a 3.7 kg mass and various celestial bodies, specifically the Earth, the Moon, and the Sun. Participants are tasked with determining the ratio of these gravitational forces, exploring the implications of their calculations and the underlying physics principles.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the gravitational force calculations using the formula F=GMm/r^2, questioning the interpretation of the problem and the significance of the ratio of forces. There is confusion regarding whether to include the gravitational force between the Sun and the Moon in their calculations.

Discussion Status

Some participants have provided calculations for the gravitational forces, while others are questioning the reasonableness of the results and the assumptions made. There is acknowledgment of the need to clarify the nature of the ratio being discussed, particularly regarding units and the relative magnitudes of the forces involved.

Contextual Notes

Participants note that the ratio of forces should be dimensionless, as units cancel out, and there is an ongoing exploration of the implications of the calculated values in relation to gravitational interactions.

Albert24
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1. Homework Statement
Calculate the magnitude of the gravitational force between the Earth and a 3.7 kg mass on the surface of the earth. The distance to the center of the Earth from the surface is 6370 km and the mass of the Earth is 5.98·1024.
That gave me 36.37 N

Calculate the magnitude of the gravitational force between the moon and a 3.7 kg mass on the surface of the Earth nearest to the moon. The distance to the center of the moon from the surface of the Earth is 376,000 km and the mass of the moon is 7.36·1022 kg.
That gave me 1.285×10-4 N

Calculate the ratio of the magnitude of the gravitational force between a 3.7 kg mass on the surface of the Earth due to the sun to that due to the moon. The mass of the sun is 1.99·1030 kg and the distance from the center of the sun to the surface of the Earth is 1.50·108 km. ?


2. Homework Equations

F=GMm/r^2

The Attempt at a Solution


I don't quite understand the problem, is it asking what is the magnitude of the gravitonial force between the mass and the sun taking in count the gravitational force between sun anf the moon? In that case the ratio=
GM1m2/r^2/GM1m2/r^2 ??
 
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Albert24 said:
1. Homework Statement
Calculate the magnitude of the gravitational force between the Earth and a 3.7 kg mass on the surface of the earth. The distance to the center of the Earth from the surface is 6370 km and the mass of the Earth is 5.98·1024.
That gave me 36.37 N

Calculate the magnitude of the gravitational force between the moon and a 3.7 kg mass on the surface of the Earth nearest to the moon. The distance to the center of the moon from the surface of the Earth is 376,000 km and the mass of the moon is 7.36·1022 kg.
That gave me 1.285×10-4 N

Calculate the ratio of the magnitude of the gravitational force between a 3.7 kg mass on the surface of the Earth due to the sun to that due to the moon. The mass of the sun is 1.99·1030 kg and the distance from the center of the sun to the surface of the Earth is 1.50·108 km. ?


2. Homework Equations

F=GMm/r^2

The Attempt at a Solution


I don't quite understand the problem, is it asking what is the magnitude of the gravitonial force between the mass and the sun taking in count the gravitational force between sun anf the moon? In that case the ratio=
GM1m2/r^2/GM1m2/r^2 ??
No, the problem is asking what is the gravitational force between the sun and a 3.7 kg mass on the surface of the earth. Call this force Fsun.
You calculated the gravitational force between this same object on the Earth's surface due to the moon, Fmoon, to be 1.285×10-4 N.

What is the ratio Fsun / Fmoon ?
 
Thanks it was 171 N
 
Albert24 said:
Thanks it was 171 N
Can't be.

1. A ratio of two forces has no units.
2. You're saying that the force exerted by the sun on an object sitting on the Earth is orders of magnitude greater than what Earth's gravity exerts on that same object.
Do you think that's reasonable?
 
SteamKing said:
2. You're saying that the force exerted by the sun on an object sitting on the Earth is orders of magnitude greater than what Earth's gravity exerts on that same object.
Do you think that's reasonable?
It's the ratio of the Sun's force to the Moon's force on an object located near the surface of the Earth.
 
I am sorry you are right there are no units they cancel out, since I was working with forces I had Newton in mind :smile:
 

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