Ratio problem: The ratio of Liquid X to Liquid Y in a mixture is 3 to 7

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SUMMARY

The ratio of Liquid X to Liquid Y in a mixture is definitively established as 3 to 7. Given that the amount of Liquid Y is 161, the calculation for Liquid X can be derived using the ratio formula. By applying the equation X = (3/7) * 161, the amount of Liquid X in the mixture is calculated to be 69. The total mixture can be inferred as 161 + 69 = 230.

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The ratio of Liquid X to Liquid Y in a mixture is 3 to 7. If the amount of Liquid Y in a mixture is 161, then the amount of Liquid x in the mixture is equal to?
 
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Let $m$ be the total amount in the mixture. Then,

$$Y=\frac{7m}{10}=161$$

From that, can you find the amount for $X$, i.e. $\frac{3}{10}$ of the mixture?
 
Personally I wouldn't worry about the total amount at all. You are told that "ratio of Liquid X to Liquid Y in a mixture is 3 to 7" so [math]\frac{X}{Y}= \frac{3}{7}[/math]. You are told that "the amount of Liquid Y in a mixture is 161" so [math]\frac{X}{161}= \frac{3}{7}[/math]. [math]X= \frac{3}{7}(161)[/math].
 

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