MHB Ratio problem: The ratio of Liquid X to Liquid Y in a mixture is 3 to 7

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The ratio of Liquid X to Liquid Y in a mixture is 3 to 7. If the amount of Liquid Y in a mixture is 161, then the amount of Liquid x in the mixture is equal to?
 
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Let $m$ be the total amount in the mixture. Then,

$$Y=\frac{7m}{10}=161$$

From that, can you find the amount for $X$, i.e. $\frac{3}{10}$ of the mixture?
 
Personally I wouldn't worry about the total amount at all. You are told that "ratio of Liquid X to Liquid Y in a mixture is 3 to 7" so [math]\frac{X}{Y}= \frac{3}{7}[/math]. You are told that "the amount of Liquid Y in a mixture is 161" so [math]\frac{X}{161}= \frac{3}{7}[/math]. [math]X= \frac{3}{7}(161)[/math].
 
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