Reactants of CO2: NaOH & H2CO3 |Chemical Reactions

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SUMMARY

The discussion focuses on the chemical reactions involving carbon dioxide (CO2) with sodium hydroxide (NaOH) and carbonic acid (H2CO3). The proposed reaction NaOH + H2CO3 → 2CH3COONa + 2H2O + 5O2 is incorrect. The correct approach involves breaking down the reactants into their ionic components: Na+ + OH− + H+ + CO3²−. The product of interest, sodium acetate (CH3COONa), is formed through proper acid-base reaction mechanisms.

PREREQUISITES
  • Understanding of acid-base reactions
  • Familiarity with ionic compounds and their dissociation
  • Knowledge of chemical reaction balancing
  • Basic concepts of CO2 chemistry
NEXT STEPS
  • Research the correct products of NaOH and H2CO3 reactions
  • Study the dissociation of ionic compounds in aqueous solutions
  • Learn about acid-base reaction mechanisms in organic chemistry
  • Explore the properties and applications of sodium acetate (CH3COONa)
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Chemistry students, educators, and anyone interested in understanding acid-base reactions and the behavior of carbon dioxide in chemical processes.

rajavarshney
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I want to ask that which element can react with CO2 gas to split c and o or what will happen if NaOH reacts with h2co3 NaOH+H2CO3---> 2CH3COONa+2H2O+5O2 IS IT CORRECT?
 
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rajavarshney said:
I want to ask that which element can react with CO2 gas to split c and o or what will happen if HNO3 reacts with h2co3


1) CO2+A---> ?
2) HNO3+H2CO3---> ?
Hi rajavarshney.

I doubt that anyone here is going to provide you with the answers to your homework. You should be able to answer the first by a google search and some easy reading, or I think you will find it in most high school science textbooks in the section on CO2 chemistry.

Good luck!
 
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rajavarshney said:
I want to ask that which element can react with CO2 gas to split c and o or what will happen if NaOH reacts with h2co3


NaOH+H2CO3---> 2CH3COONa+2H2O+5O2 IS IT CORRECT?
Physicsforums frowns on users editing their original post so drastically that it becomes a new & different question. I recommend that you never do that again.

To help in deducing how acid-base reactions may proceed, it will help you immensely if you first break the reagents into their ionic parts:

Na+ + OH + H+ + CO3= ⟶ ...

In these reactions, it is almost always the simplest looking re-arrangement that you should try for.

BTW, the compound CH3COONa is named sodium acetate.

I hope you enjoy your study of chemistry as much as I did!
 

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