Reaction of 118 elements simultaneously = product?

Click For Summary

Discussion Overview

The discussion revolves around the hypothetical reaction involving all 118 elements of the periodic table simultaneously. Participants explore the nature of such a reaction, the potential products, and the conditions under which these elements might interact, including considerations of fusion and mixing at normal temperatures.

Discussion Character

  • Exploratory
  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • One participant questions the clarity of the original inquiry, asking what specific reaction is being considered with all 118 elements.
  • Another suggests that if fusion reactions are meant, the outcome would be a complex mixture of different elements and isotopes, though they do not specify what those might be.
  • It is proposed that mixing all elements at normal temperature would yield an unpredictable mixture of products, influenced by the reactivity of the elements involved.
  • A participant humorously references the potential dangers of certain elements reacting, particularly those that could cause destruction if synthesized in significant quantities.
  • A thought experiment is introduced regarding the most thermodynamically stable configuration of one atom of each element at standard temperature and pressure, noting the lack of sufficient data on heats of formation to determine this definitively.

Areas of Agreement / Disagreement

Participants express varying interpretations of the original question, with no consensus on the nature of the reaction or the resulting products. Multiple competing views remain regarding the outcomes of mixing or reacting the elements.

Contextual Notes

The discussion highlights limitations in predicting outcomes due to the complexity of interactions between highly reactive elements and the lack of comprehensive data on the properties of all elements involved.

hyunxu
Messages
54
Reaction score
16
This may be bit weird but really do we get any product after the reaction of 118 elements of the periodic table.We know masses of reactant = masses of product.But no so in nuclear fission and fusion.Anyhow finally what might be that product?and what is going to be its state.Please explain me well because I'm just a school student.

Waiting for your best responses.
images (12).jpeg
 

Attachments

  • images (12).jpeg
    images (12).jpeg
    14 KB · Views: 779
Chemistry news on Phys.org
Hi hyunxu. It's not clear to me what you're asking. What is reacting? All 118 elements of the periodic table at the same time? What kind of reaction are you asking about?
 
Drakkith said:
Hi hyunxu. It's not clear to me what you're asking. What is reacting? All 118 elements of the periodic table at the same time? What kind of reaction are you asking about?
I mean like mixing all the sliced fruits together in a fruit salad.
 
If you mean fusion reactions, then you'll get a mess of different elements and isotopes. I wouldn't be able to even begin to list them all.
 
On the other hand, if you will mix all elements at normal temperature (that is, far from conditions required for fusion) you will get some difficult to predict mixture of products. More reactive elements will react quickly, the less reactive ones will stay inert or get passivated. Final result would depend on many factors, like the initial form of the elements and their relative initial amounts.
 
  • Like
Likes   Reactions: baldbrain and hyunxu
  • Like
Likes   Reactions: krater, Tom.G, hyunxu and 1 other person
Borek said:
On the other hand, if you will mix all elements at normal temperature (that is, far from conditions required for fusion) you will get some difficult to predict mixture of products.

Oh, I think I can predict what will happen when the cesium and the fluorine get together...

 
Perhaps an interesting thought experiment: Assume you have one atom of each of the 118 elements. Given standard temperature and pressure, what is the most thermodynamically stable configuration of those atoms?

We probably don't have enough data on heats of formation to determine the answer, but there should at least be a unique answer to the question in theory (at least w/o complications from the decay chains of the radioactive elements).
 

Similar threads

Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
10K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 29 ·
Replies
29
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
5
Views
3K
Replies
7
Views
6K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
5K