# Reaction that does not reach equilibrium

## Homework Statement

Will you expect the reaction C(s) + CO2(g) = 2CO(g) to reach equilibrium at 298K?

## The Attempt at a Solution

Yes, because all reactions reach equilibrium given enough time.

Am I wrong? My book says so. The answer is simply "no". But why?

mgb_phys
Homework Helper
All reactions reach 'an' equlibrium at a certain temperature.

Imagine mixing hydrogen and oxygen, at room temperature the equilibrium is for it to form water - on the surface of a star it won't.

So the answer is no because CO is not stable at 298K? And that can be seen because the gibbs free energy for the reaction is positive from left to right?

Mapes
Homework Helper
Gold Member
Yes, because all reactions reach equilibrium given enough time.

I'm with you on this one. It's too bad the answer couldn't have been more specific (e.g., a reasonable amount of time). It makes it hard to understand what's expected of you.

Even if the production of CO isn't favored, the reaction should still reach equilibrium--just with very little CO in the system.

Borek
Mentor
Am I wrong? My book says so. The answer is simply "no". But why?

Change the book.

It may take eons, but finally reaction will reach the equilibrium.

Could be they meant something else than they asked - but if so, change the book.

GCT
Homework Helper
This question is concerns the equilibrium as pertaining to free energy and at room temperature the free energy for the reaction may not be zero meaning that either the forward or reverse mechanism is favored ; this does not mean that things are not going to stabilize at some point however this latter point is different from the actual concept of equilibrium.

Remember that the equilibrium is at the temperature where the free energy is zero. Use the a derivation of the Gibbs equation along with the standard Gibbs potential value to solve for the temperature.

Mapes