Really weird physics problem, can you help me?

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The discussion revolves around a physics problem involving the calculation of Earth's radius based on the time it takes for the Sun to disappear after standing up from a lying position. Participants emphasize the importance of a clear diagram and understanding the trigonometric relationships involved, noting that the radius of the Earth is an unknown variable. There is confusion regarding the application of the law of cosines due to having two unknowns and only one equation. A moderator encourages the original poster to attempt a solution before receiving further assistance. The conversation concludes with a participant expressing newfound clarity after receiving guidance.
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Suppose that, while lying on a beach near the equator watching the Sun set over a calm ocean, you start a stopwatch just as the top of the Sun disappears. You then stand, elevating your eyes by a height H = 1.70 m, and stop the watch when the top of the Sun again disappears. If the elapsed time is t = 11.1 s, what is the radius r of Earth?
 
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Use the celestial sphere to solve the problem.
 
Hi TrevorRyan! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:

(you'd better start with a really good diagram!)
 
Yes, an accurate diagram would really benifit
 
Looks like a trigonometry problem. You are given two sides and the angle between them.
 
sacscale said:
Looks like a trigonometry problem. You are given two sides and the angle between them.

How so? You can figure the angle that the Earth rotates in the problem, but you aren't given the sides that enclose that angle.
 
tiny-tim said:
Hi TrevorRyan! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:

(you'd better start with a really good diagram!)

I'd like to see a better description on that first sentence too.
 
Nessdude14 said:
How so? You can figure the angle that the Earth rotates in the problem, but you aren't given the sides that enclose that angle.

One side is the radius the other is the radius plus 1.70m.
 
sacscale said:
One side is the radius the other is the radius plus 1.70m.

Those sides aren't given, the radius of the Earth is an unknown in this problem. If you try to apply the law of cosines, you get 2 unknowns and only one equation.
 
  • #10
Nessdude14 said:
Those sides aren't given, the radius of the Earth is an unknown in this problem. If you try to apply the law of cosines, you get 2 unknowns and only one equation.

At the tangent to the surface is a right angle.
 
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  • #11
Moderator's note

At this point, please let TrevorRyan respond with an attempt toward working out the problem, in accordance with our forum guidelines on Homework Help. Please do not post further hints and help until we here from the OP.
 
  • #12
I always get to the this equation, R+1.7cos0.04625=R, and Have no idea what to do from there.
 
  • #13
Add parentheses at the proper places? Your equation means that 1.7 cos0.04625=0 which is obviously wrong.

For better understanding, I attach the missing figure. One sees the sunset when the ray arriving to the eye from the sun is tangent to the Earth.

ehild
 

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  • #14
wow I am retarded lol. Thx ehild, now i get it
 
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